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      • Equilibrium” is the seventh chapter in the NCERT Class 11 Chemistry Textbook. Several important concepts, such as equilibrium constants, buffer solutions and the common-ion effect, are explained in this chapter.
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  2. Jan 19, 2024 · Equilibrium Class 11 Notes Chemistry Chapter 7. • Chemical Equilibrium. In a chemical reaction chemical equilibrium is defined as the state at which there is no further change in concentration of reactants and products. For example, At equilibrium the rate of forward reaction is equal to the rate of backward reaction.

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      CBSE Class 11 Chemistry Notes and short key-notes to score...

    • Some Basic Concepts Of Chemistry. Importance and scope of Chemistry. Laws of chemical combination. Dalton’s atomic theory. Atoms and molecules. Atomic and molecular masses.
    • Structure Of Atom. Discovery of Electron. Proton and Neutron. Atomic number. Isotopes and isobars. Thomson’s model and its limitations. Rutherford’s model and its limitations.
    • Classification of Elements and Periodicity. Significance and development of periodic table. Modern periodic law and the present form of periodic table. Periodic trends in properties of elements.
    • Chemical Bonding And Molecular Structure. Valence electrons. Ionic bond. Covalent bond. Bond parameters. Lewis structure. Polar character of covalent bond. Covalent character of ionic bond.
  3. NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium is provided on this page for the CBSE Class 11 students to study and prepare well for the annual exam. Detailed, step-by-step solutions for each and every intext and exercise question listed in Chapter 7 of the NCERT Class 11 Chemistry textbook can be accessed here.

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    • What is chemistry Chapter 7 in CBSE Class 11?1
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  4. Apr 24, 2024 · CBSE Class 11 Chemistry Notes Chapter 7: The term “chemical equilibrium” describes the point at which neither the reactants nor the products may alter anymore. The advancing and backward reaction rates stay the same in this scenario. It becomes crucial for students to understand equilibrium to understand more complex subjects.

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    • Ncert Textbook Questions Solved
    • Ncert Solutions For Class 11 Chemistry Chapter 7 Short Answer Type Questions
    • Ncert Solutions For Class 11 Chemistry Chapter 7 Long Answer Type Questions
    • Ncert Solutions For Class 11 Chemistry Chapter 7 Multiple Choice Questions
    • Ncert Solutions For Class 11 Chemistry Chapter 7 Hots Questions

    Question 1. A liquid is in equilibrium with its vapours in a sealed container at a fixed temperature. The volume of the container is suddenly increased, (i) What is the initial effect of the change on the vapour pressure? (ii) How do the rates of evaporation and condensation change initially? (iii) What happens when equilibrium is restored finally ...

    Question 1. The following concentration were obtained for the formation of NH3 from N2 and H2 at equilibrium at 500 K.[N2(g)] = 1.5 x 10-2 M [H2 (g)] = 3.0 x 10-2 M [NH3] = 1.2 x 10-2 M. Calculate equilibrium constant. Answer: Question 2. Write the equilibrium constant (Kc) expression for the following reactions. Answer: Question 3. Given the equil...

    Question 1. (i) Point out the differences between ionic product and solubility product. (ii) The solubility of AgCl in water at 298 K is 1.06 x 10-5 mole per litre. Calculate its solubility product at this temperature. Answer: (i) Question 2. At certain temperature and under a pressure of 4 atm, PCl5 is 10% dissociated. Calculate the pressure at wh...

    Question 1. The equilibrium expression, Kc= [C02] represents the reaction. Question 2. Hydrogen molecule (H2) can be dissociated into hydrogen atoms (H). Which one of the following changes will not increase the number of atoms present at equilibrium? (a) adding H atoms (b) increasing the temperature (c) increasing the total pressure (d) increasing ...

    Question 1. For the equilibrium 2 NOCl(g)——-> 2NO(g) + Cl2(g) the value of the equilibrium constant Kc is 3.75 x 10-6 at 1069 K. Calculate the Kp for the reaction at this temperature? Answer: We know that Kp = Kc(RT)∆n For the above reaction, ∆n = (2 + 1) – 2 = 1 Kp = 3.75 x 10’6 (0.0831 x 1069) Kp= 0.033. Question 2. The values of Ksp of two spari...

  5. Important Questions. 1. While writing the equilibrium constant expression, you can ignore pure liquids and solids. Why? Explain. 2. Tick mark Lewis acids from the following. H 2 O, H +, NH +4 and BF 3. 3. Below are Brönsted bases. Write the conjugate acids for the same. NH 2–, HCOO –, NH 3.

  6. Apr 9, 2024 · Class 11 Chemistry chapter 7 notes are designed using the most recent NCERT Syllabus and CBSE guidelines. Students can turn to the following resources for extra information on any topic covered in this chapter. Also, students can refer, NCERT Notes Class 11 Chemistry.