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NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium is provided on this page for the CBSE Class 11 students to study and prepare well for the annual exam. Detailed, step-by-step solutions for each and every intext and exercise question listed in Chapter 7 of the NCERT Class 11 Chemistry textbook can be accessed here.
- NCERT Solutions for Class 11 Chemistry Chapter 7 - Equilibrium
NCERT Solutions for Class 11 Chemistry Chapter 7 -...
- NCERT Solutions for Class 11 Chemistry Chapter 7 - Equilibrium
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Question 1. A liquid is in equilibrium with its vapours in a sealed container at a fixed temperature. The volume of the container is suddenly increased, (i) What is the initial effect of the change on the vapour pressure? (ii) How do the rates of evaporation and condensation change initially? (iii) What happens when equilibrium is restored finally ...
Question 1. The following concentration were obtained for the formation of NH3 from N2 and H2 at equilibrium at 500 K.[N2(g)] = 1.5 x 10-2 M [H2 (g)] = 3.0 x 10-2 M [NH3] = 1.2 x 10-2 M. Calculate equilibrium constant. Answer: Question 2. Write the equilibrium constant (Kc) expression for the following reactions. Answer: Question 3. Given the equil...
Question 1. (i) Point out the differences between ionic product and solubility product. (ii) The solubility of AgCl in water at 298 K is 1.06 x 10-5 mole per litre. Calculate its solubility product at this temperature. Answer: (i) Question 2. At certain temperature and under a pressure of 4 atm, PCl5 is 10% dissociated. Calculate the pressure at wh...
Question 1. The equilibrium expression, Kc= [C02] represents the reaction. Question 2. Hydrogen molecule (H2) can be dissociated into hydrogen atoms (H). Which one of the following changes will not increase the number of atoms present at equilibrium? (a) adding H atoms (b) increasing the temperature (c) increasing the total pressure (d) increasing ...
Question 1. For the equilibrium 2 NOCl(g)——-> 2NO(g) + Cl2(g) the value of the equilibrium constant Kc is 3.75 x 10-6 at 1069 K. Calculate the Kp for the reaction at this temperature? Answer: We know that Kp = Kc(RT)∆n For the above reaction, ∆n = (2 + 1) – 2 = 1 Kp = 3.75 x 10’6 (0.0831 x 1069) Kp= 0.033. Question 2. The values of Ksp of two spari...
Get free NCERT Solutions for Chemistry Part 1 and 2 Class 11 Chapter 7 Equilibrium solved by experts. Available here are Chapter 7 - Equilibrium Exercises Questions with Solutions and detail explanation for your practice before the examination
NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium: In this chapter, students learn Equilibrium in physical and chemical processes, dynamic nature of equilibrium, the law of mass action, equilibrium constant, factors affecting equilibrium - Le Chatelier's principle, ionic equilibrium- ionisation of acids and bases, strong and weak ...
Mar 14, 2024 · Q.1: Which is the best solution for NCERT Class 11 Chapter 7 Chemistry? Ans: Students can find 100% accurate Solutions of the NCERT Class 11 Chemistry Chapter 7, Equilibrium on the Embibe platform. This article contains the complete solution solved by expert Chemistry teachers associated with Embibe.
Aug 22, 2022 · Download PDF. NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium- In this chapter, you will get the NCERT solutions for class 11 chemistry chapter 7 Equilibrium of chemical and physical processes and details about equilibrium's dynamic nature.
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NCERT Solutions for Class 11 Chemistry Chapter 7 - Equilibrium . Q.1. A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. What is the initial effect of the change on vapour pressure? How do rates of evaporation and condensation change initially?
