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Nov 20, 2016 · In your case, you want to split a string when there is a "-". You can simply do as follows: String str = "004-034556"; String split[] = StringUtils.split(str,"-"); Output: 004. 034556. Assume that if - does not exists in your string, it returns the given string, and you will not get any exception.
Oct 5, 2016 · 15. Use Stringutils.split() to split the string by whites paces. For example StringUtils.split("Hello World") returns "Hello" and "World"; In order to solve the mentioned case we use split method like this. String split[]= StringUtils.split("Hello I'm your String"); when we print the split array the output will be :
private void getId(String pdfName){ String[] tokens = StringUtils.split(pdfName, "-."); It'll split on any of the specified separators, as opposed to StringUtils.splitByWholeSeparator(str, separator) which uses the complete string as a separator
Dec 2, 2017 · 1. If the original string contains supplementary Unicode characters, then split() would not work, as it splits these characters into surrogate pairs. To correctly handle these special characters, a code like this works: String[] chars = new String[stringToSplit.codePointCount(0, stringToSplit.length())];
Feb 14, 2020 · myString.split("\\s+"); This groups all white spaces as a delimiter. So if I have the string: "Hello[space character][tab character]World". This should yield the strings "Hello" and "World" and omit the empty space between the [space] and the [tab]. As VonC pointed out, the backslash should be escaped, because Java would first try to escape the ...
May 17, 2012 · 405. You could do this: String str = "..."; List<String> elephantList = Arrays.asList(str.split(",")); Basically the .split() method will split the string according to (in this case) delimiter you are passing and will return an array of strings. However, you seem to be after a List of Strings rather than an array, so the array must be turned ...
Jul 30, 2012 · It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead. – Tomor Commented Jan 6, 2018 at 19:24
Feb 12, 2013 · 965. You need to escape the dot if you want to split on a literal dot: String extensionRemoved = filename.split("\\.")[0]; Otherwise you are splitting on the regex ., which means "any character". Note the double backslash needed to create a single backslash in the regex.
Apr 19, 2014 · You can create an ArrayList from the array via Arrays.asList: ArrayList<String> parts = new ArrayList<>(. Arrays.asList(textField.getText().split(","))); If you don't need it to specifically be an ArrayList, and can use any type of List, you can use the result of Arrays.asList directly (which will be a fixed-size list): List<String> parts ...
Sadly, Java lacks a both simple and efficient method for splitting a string by a fixed string. Both String::split and the stream API are complex and relatively slow. Also, they can produce different results. String::split examines its input, then compiles to java.util.regex.Pattern every time (except if the input contains only a single char ...
