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Mar 4, 2024 · Smallest window in a String containing all characters of other String using Two Pointers and Hashing: The idea is to use the two pointer approach on the hash array of pattern string and then find the minimum window by eliminating characters from the start of the window. Follow the steps below to solve the problem:
Given strings str1 and str2, find the minimum (contiguous) substring W of str1, so that str2 is a subsequence of W. If there is no such window in str1 that covers all characters in str2, return the empty string "".
Given two strings S and P. Find the smallest window in the string S consisting of all the characters(including duplicates) of the string P. Return "-1" in case there is no such window present. In case there are multiple such
Minimum Window Substring - Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, return the empty string "".
class Solution { public: string minWindow(string s, string t) { vector<int> count(128); int required = t.length(); int bestLeft = -1; int minLength = s.length() + 1; for (const char c : t) ++count[c]; for (int l = 0, r = 0; r < s.length(); ++r) { if (--count[s[r]] >= 0) --required; while (required == 0) { if (r - l + 1 < minLength) { bestLeft = ...
Jul 31, 2023 · To find the minimum window substring, we utilize a sliding window technique. We start with two pointers, left and right, that define the window boundaries. We expand the window by moving the...
-export([min_window/0]). %% Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). %% For example, %% S = "ADOBECODEBANC" %% T = "ABC" %% Minimum window is "BANC". %% Note: %% If there is no such window in S that covers all characters in T, return the emtpy string "".
