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Given the root of a binary tree, return the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
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In-depth solution and explanation for LeetCode 543. Diameter of Binary Tree in Python, Java, C++ and more. Intuitions, example walk through, and complexity analysis. Better than official and forum solutions.
543. Diameter of Binary Tree Initializing search walkccc/LeetCode
The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root. The length of a path between two nodes is represented by the number of edges between them. Example 1: Input: root = [1,2,3,4,5] Output: 3.
Problem: Given the root of a binary tree, return the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Jan 16, 2023 · The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root. The length of a path between two nodes is represented by the number of edges between them.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root. The length of a path between two nodes is represented by the number of edges between them. Example 1: Input: root = [1,2,3,4,5] Output: 3.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root. The length of a path between two nodes is represented by the number of edges between them. Example 1 : Input: root = [1,2,3,4,5] Output: 3. Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].
class Solution: def diameterOfBinaryTree(self, root: Optional[TreeNode]) -> int: max_diameter = 0. # Walk through each tree node and computer its diameter. stk = [root] while len(stk) > 0: # Pop tree node from the stack. c = stk.pop() # Current node's diameter = left tree height + right tree height.
