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  1. Diameter of a Binary Tree. Difficulty: Medium Accuracy: 47.37% Submissions: 287K+ Points: 4. The diameter of a tree (sometimes called the width) is the number of nodes on the longest path between two end nodes.

  2. 6 days ago · The diameter of given binary tree is 4. Time Complexity: O (N), where N is the number of nodes in the binary tree. Auxiliary Space: O (h), The Morris Traversal approach does not use any additional data structures like stacks or queues, which leads to an auxiliary space complexity of O (1).

  3. Given a binary tree of size n, you have to count the number of nodes in it. For example, the count of nodes in the tree below is 4. 1 / \ 10 &nb.

  4. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root. The length of a path between two nodes is represented by the number of edges between them.

  5. practice.geeksforgeeks.org › problems › diameter-of-binary-treeGeeksforGeeks

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  7. The diagram below shows two trees each with diameter nine, the leaves that form the ends of a longest path are shaded (note that there is more than one path in each tree of length nine, but no path longer than nine nodes).

  8. May 22, 2024 · Given a Binary Indexed Tree with N nodes except root node 0 (Numbered from 1 to N), Find its diameter. Binary Indexed Tree is a tree where parent of a node number X = X - (X & (X - 1)) i.e. last bit is unset in X. The diameter of a tree is the longest simple path between any two leaves. Examples: Input: N = 12 Output: 6 Explanation: Path from n

  9. Oct 21, 2021 · Given a binary tree, write an efficient algorithm to compute the diameter of it. A binary tree diameter equals the total number of nodes on the longest path between any two leaves in it. The following figure shows two binary trees with diameters 6 and 5, respectively (nodes highlighted in blue).

  10. Sep 13, 2017 · Find Complete Code at GeeksforGeeks Article: http://www.geeksforgeeks.org/diameter-of-a-binary-tree/Practice Problem Online Judge: http://practice.geeksforge...