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Two water taps together can fill a tank in 93 8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank. Solution. Let the time taken by the smaller pipe to fill the tank be x hr. Time taken by the larger pipe = (x - 10) hr.
Apr 16, 2024 · Ex 4.3 ,9 Two water taps together can fill a tank in 9 3/8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
Two water taps together can fill a tank in 9 3/8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank. Solution: Let the tap of smaller diameter fill the tank in x hours. The tap of larger diameter takes (x - 10) hours.
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Two water taps together can fill a tank in 93 8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time (in hrs.) in which tap of smaller diameter can separately fill the tank. View Solution.
Short Answer. Expert verified. The larger tap can fill the tank in 25 hours, and the smaller tap can fill it in 35 hours. Step by step solution. 01. Convert mixed fraction to improper fraction. First, convert the mixed fraction for the time taken by both taps to fill the tank to an improper fraction to simplify calculations.
Apr 16, 2024 · Two water taps together can fill a tank in 9 3/8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank
Sep 25, 2024 · Two water taps can together fill a tank in \[9\dfrac{3}{8}\] hours. The tap of larger diameter takes 10 hours less than the tap of smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
