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Learn how to calculate the fringe width and position of bright and dark fringes in Young's double slit experiment using monochromatic light. Find the expressions for fringe width, angular width, and fringe shift in different cases and examples.
- Young’s Double Slit Experiment Derivation
- Theory of The Experiment
- Derivation of Young’s Double Slit Experiment
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Young placed a monochromatic source (S) of light in front of a narrow slit S0 and arranged two very narrow slits S₁ and S₂ close to each other in front of slit S0 young’s double slit experiment derivation diagram below. Slits S₁ and S₂ are equidistant from S0, so the spherical wavefronts emitted by slit S0reach the slits S₁ and S₂ in equal time. Th...
Suppose S is the monochromatic source of light. S0is the slit through which the light passes and illuminates the slits S₁ and S₂. The waves emitted by slits S₁ and S₂ are the part of the same wavefront, so these waves have the same frequency and the same phase. Hence slits S1 and S2 behave as two coherent sources. Interference takes place on the sc...
To locate the position of the maxima and minima on both sides of O, consider any point P at a distance x from O. Join S1P and S2P. Now draw S1N normal on S2P. Then the path difference between S2P and S1P Now from △S1PL, and from △S2PM, Since the distance of screen from slits S1 and S2 is very large, so S2P ≈S1P ≈D Path difference,
Learn how to calculate the fringe width of bright and dark fringes in Young's double slit experiment using the path difference formula. Find the fringe width formula and examples of interference patterns on the screen.
Fringe width is the distance between two consecutive bright spots (maximas, where constructive interference take place) or two consecutive dark spots (minima...
- 12 min
- 64K
- Khan Academy India - English
In this video we have discussed about the one of the major topic of our wave optics that is fringe width in interference of light by young's double slit expe...
- 10 min
- 74.4K
- Science Analytica
Sep 12, 2022 · The diffraction pattern of two slits of width \(a\) that are separated by a distance d is the interference pattern of two point sources separated by d multiplied by the diffraction pattern of a slit of width \(a\). In other words, the locations of the interference fringes are given by the equation \[d \, \sin \, \theta = m \lambda \nonumber \]
Learn how to calculate the fringe width in a YDSE using the equation ω = λD/d. See examples, diagrams and explanations of the interference pattern and optical path length.
4 days ago · Learn how to derive the formula for fringe width in Young's double slit experiment using superposition principle and wave equation. Find out how a glass slab introduces a lateral shift of fringe and affects the intensity pattern.
