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- Dictionaryflag/flaɡ/
noun
- 1. a piece of cloth or similar material, typically oblong or square, attachable by one edge to a pole or rope and used as the symbol or emblem of a country or institution or as a decoration during public festivities: "the American flag"
- 2. a small piece of cloth attached at one edge to a pole and used as a marker or signal in various sports: "the flag's up"
verb
- 1. mark (an item) for attention or treatment in a specified way: "the spellcheck program flags any words that are not in its dictionary"
- 2. (of an official) raise a flag to draw the referee's attention to a breach of the rules in soccer, rugby, and other sports: "the goalkeeper brought down Hendrie and a linesman immediately flagged"
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A good way to understand what the preprocessor does to your code is to get hold of the preprocessed output and look at it. This is how to do it for Windows: Create a simple file called test.cpp and put it in a folder, say c:\temp. Mine looks like this: #define dog_suffix( variable_name ) variable_name##dog. int main()
Jan 26, 2012 · 1.) target_compile_definitions. If you are using CMake 3.X your first choice for adding a preprocessor macro should be target_compile_definitions. The reason you should prefer this approach over any other approach is because it granularity is target based. IE the macro will only be added to your exe/library.
Aug 12, 2008 · 1. You don't need the [Flags] attribute to make this work. It will also work without. The only thing the [Flags] attribute does is change is the result of the ToString() of the enum. When you have an enum value Driver | Admin, without [Flags] it will print 6, and with [Flags] attribute it will print as Driver, Admin.
Jun 20, 2016 · 4. Any #define that you want to use to inject bitflags into a struct must take the form: #define IDENTIFIER SUBSTITUTED_CODE. In your postulated use... #define FLAG_FAILED:1. The identifier contains the colon, which makes it invalid. You could do something like this: #define FLAG_FAILED int flag_failed :1. struct X.
Nov 13, 2018 · Also see Passing a gcc flag through makefile, Append compile flags to CFLAGS and CXXFLAGS while configuration/make, How to add compile flag -g to a make file?, Allowing users to override CFLAGS, CXXFLAGS and friends, Including a #define in all .c source files at compile time, Precedence of -D MACRO and #define MACRO etc.
Nov 30, 2019 · 6. A flag in Python acts as a signal to the program to determine whether or not the program as a whole or a specific section of the program should run. In other words, you can set the flag to True and the program will run continuously until any type of event makes it False. Then the program, loop, or whatever you're using a flag for will stop.
Sep 19, 2009 · Note if you are working in Windows environment, there is a DEFINE_ENUM_FLAG_OPERATORS macro defined in winnt.h that does the job for you. So in this case, you can do this: enum AnimalFlags { HasClaws = 1, CanFly =2, EatsFish = 4, Endangered = 8 }; DEFINE_ENUM_FLAG_OPERATORS(AnimalFlags) seahawk.flags = CanFly | EatsFish | Endangered;
Dec 10, 2019 · A flag variable, it is a variable you define to have one value until some condition is true or false in which case you change the variable's value. It is a variable you can use to control the flow of a function or statement, allowing you to check for certain conditions while your function executing. Flag variable is same in every language.
Aug 3, 2012 · SET(GCC_COVERAGE_LINK_FLAGS "-lgcov") There are several ways to add them: The easiest one (not clean, but easy and convenient, and works only for compiler flags, C & C++ at once): add_definitions(${GCC_COVERAGE_COMPILE_FLAGS}) Appending to corresponding CMake variables: SET(CMAKE_CXX_FLAGS "${CMAKE_CXX_FLAGS} ${GCC_COVERAGE_COMPILE_FLAGS}") SET ...
Jun 30, 2015 · However, if you really want to use DEBUG=0, this is how you can do it: Each time you define the DEBUG flag (i.e., in each file), check for an existing definition: #ifndef DEBUG #define DEBUG 1 #endif Then, when you use the option -DDEBUG=0 with your compiler, the #define line will never be executed.