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Solution: We can find the angular momentum by using the formula, and the moment of inertia of a solid disc (ignoring the hole that is present in the middle). The angular momentum will be: L = I ω. L = (12MR2)ω. So, L = 12(0.0200kg)(0.0600m)2(160.0radians/s) L = 0.00576 kg. m2 /s. The angular momentum of this DVD will be 0.00576 kg. m2 /s.
Angular Momentum. Torque and angular momentum are closely related to each other. Angular momentum is the rotational analogue of linear momentum ‘p’ and is denoted by ‘l’. It is a vector product. Angular momentum of the particle is. l = r × p. l = r p sinθ, where θ is the angle between r and p. Relation between Torque and Angular Momentum
Angular momentum can be defined as the vector product of the angular velocity of a particle and its moment of inertia. When a particle of mass m shows linear momentum (p) at a position (r) then the angular momentum with respect to its original point O is defined as the product of linear momentum and the change in position.
SI Unit of angular momentum kgm2/sAngular momentum =moment of inertia×Angular velocity....(1)Dimensional formula of moment of inertia=M1L2T0Dimensional formula of Angular velocity =M0L0T−1Putting these values in above eq. (1)So dimensional formula of angular momentum =M1L2T−1. Was this answer helpful? State S.I. unit of angular momentum ...
The angular momentum as electron is a given orbital is calculated using, Orbital angular momentum = √ l (l + 1) h 2 π. Now for d-electron, l=2
An angular moment of a satellite revolving around the earth in a circular orbit at a height R above the surface is L. Here R is the radius of the earth. The magnitude of angular momentum of another satellite of the same mass revolving very close to the surface of the earth is
An electron in an excited state of L i 2 + ion has angular momentum 3 h 2 π. The de Broglie wavelength of the electron in this state in p π α 0 (where α 0 is the Bohr radius). The value of p is
The angular momentum of an electron in 2s orbital is: View Solution. Q 5. The orbital angular momentum of an electron is √3 h π. Which of the following may be a permissible value of angular momentum of an electon revolving in an unknown Bohr's orbit?
The spin angular momentum of electron S = 3 h 4 π. Was this answer helpful? 0. Similar Questions.
Angular velocity is the rate of velocity at which an object or a particle is rotating around a center or a specific point in a given time period. It is also known as rotational velocity. Angular velocity is measured in angle per unit time or radians per second (rad/s). The rate of change of angular velocity is angular acceleration.
