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Your "indexOf" example should use >= 0, not > 0, since 0 is valid if the substring occurs at the beginning of the string. (Doesn't in your example, but could in other cases.) Added this response since people are obviously still searching and finding this answer.
public String substring(int beginIndex, int endIndex) beginIndex—the begin index, inclusive.. endIndex—the end index, exclusive.
Jan 6, 2014 · In Java we have indexOf and lastIndexOf. Is there anything like lastSubstring? It should work like : "aaple".lastSubstring(0, 1) = "e";
You can find the number of occurrences of a substring in a string using Java 9 method Matcher.results() with a single line of code. It produces a Stream of MatchResult objects which correspond to captured substrings, and the only thing needed is to apply Stream.count() to obtain the number of elements in the stream.
Dec 22, 2010 · The substring begins at the specified start and extends to the character at index end - 1. It has two forms. The first is. String substring(int FirstIndex) Here, FirstIndex specifies the index at which the substring will begin. This form returns a copy of the substring that begins at FirstIndex and runs to the end of the invoking string.
Jun 5, 2009 · Java's substring method fails when you try and get a substring starting at an index which is longer than ...
Jan 15, 2012 · String substr=mysourcestring.substring(startIndex); If you want to get substring from specific character till end you can use : String substr=mysourcestring.substring(mysourcestring.indexOf("characterValue")); If you want to get substring from after a specific character, add that number to .indexOf(char):
Oct 18, 2009 · It might also be useful to point out that StringUtils.substring(yourString, 0, n) is not the same as yourString.substring(0, n). The former is from StringUtils, while the latter is using String.substring (which gives exception if end index exceeds string length). –
String.substring(0, maxLength); Example: String aString ="123456789"; String cutString = aString.substring(0, 4); // Output is: "1234" To ensure you are not getting an IndexOutOfBoundsException when the input string is less than the expected length do the following instead:
Jul 6, 2010 · Java substring difficulty. 0. Java 1.4 sub string retreival. 1. I need some guidance on the substring ...
