Search results
- 0
Jul 27, 2016 · Prove trig identity Apply the trig identity: sin (a - b) = sin a.cos b - sin b.cos a sin (180 - a) = sin 180.cos a - sin a.cos 180 Since sin 180 = 0 and cos 180 = -1, there for sin (180 - a) = sin a
Given that: sin 180 0 we can write sin 180 o = sin ( 2 ⋅ 90 o ) = 2 sin 90 0 cos 90 o = 2 ( 1 ) ( 0 ) = 0 {Using sin 2 A = 2 sin A cos A } Was this answer helpful?
Jun 23, 2016 · We expand sin(180^0+a) using the formula sin(A+B)=sinAcosB+cosAsinB :. sin (180^0+a)=sin180^0cosa+cos180^0sina In this, 180^0=0, cos180^0=-1 :. sin(180^0+a)=-sina. Trigonometry Science
Click here:point_up_2:to get an answer to your question :writing_hand:displaystyle fracsin1800 thetacos 900 thetatan 2700 thetacot 3600 thetasin3600 theta cos
If sin6θ+ cos6θ−1 =λ sin2θ cos2θ, find the value of λ. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:find the average value of displaystyle sin 2circsin 4circsin6circsin 180circ.
Click here:point_up_2:to get an answer to your question :writing_hand:prove that dfracsin 180othetacos90othetatan 270othetacot 360othetasin360othetacos 360othetacscthetasin 270otheta1
The average value of sin 2 o, sin 4 o, sin 6 o,..... sin 180 o is :-1 90 cos 1 o; 1 90 sin 1 o; 1 90 cot 1 ...
Click here👆to get an answer to your question ️ sin(180^0 + theta)cos (90^0 + theta)tan (270^0 - theta ...
Answer: As below. Explanation: Following table gives the double angle identities which can be used while solving the equations. You can also have sin2θ,cos2θ expressed in terms of tanθ as under. sin2θ = 2tanθ 1 +tan2θ. cos2θ = 1 −tan2θ 1 +tan2θ. sankarankalyanam · 1 · Mar 9 2018.
May 30, 2015 · On the trig unit circle: sin 120 = sin (180 - 60) = sin 60 = sqrt3/2
