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Oct 15, 2010 · Note: Dec, 2023 with Python 3.11 performance improvements. I ran a quick comparison of Python 3.7 to 3.11 (on the same PC just now) with 1 million cycles to see what difference the the 3.11 performance improvements would make. Python 3.11 was 26.5% faster on average, roughly the same for manual as for built in methods of reversing lists.
Feb 10, 2009 · How do I traverse a list in reverse order in Python? So I can start from collection[len(collection)-1] and end in collection[0]. I also want to be able to access the loop index.
May 31, 2009 · >>> reversed_string('a_string') 'gnirts_a' Longer explanation. If you're interested in the academic exposition, please keep reading. There is no built-in reverse function in Python's str object. Here is a couple of things about Python's strings you should know: In Python, strings are immutable. Changing a string does not modify the string.
So you HAVE to create a list before send some iterable to reversed in many situations like reversed([expr(i) for i in iterable if cond(i)]) - without brackets it falls. – Odomontois Commented Aug 13, 2010 at 15:57
The implementation is limited in that you cannot use reversed twice and get the original back. It is not symmetric as such. It is tested with Python 2.6. Here is a use case of how I am using to print the resultant dict.
This approach is good if you do NOT need to keep the original list and you have several passes/operations to do on the elements of the reversed list and if you have to save the processed reversed list. Last but not least, using slicing [::-1] creates a new object of the list/a copy in reversed
Sep 18, 2013 · A string in Python is an array of chars, so you just have to traverse the array (string) backwards. You can easily do this like this: "Python is the best programming language"[::-1]
In Python, what is the best way to create a new list whose items are the same as those of some other list, but in reverse order? (I don't want to modify the existing list in place.) Here is one so...
Apr 16, 2017 · reversed is needed, not sorted. There is no sorting required. Three months later you come along and provide an additional wrong answer to an already answered question of the simplest possible order. Please delete this answer, for the sake of the poor noobs who read this answer and may actually try to understand what you've written. –
You have to take into account the number of bits to be reversed. For example, you want to reverse bits in a byte. You expect that 0x1 will be translated to 0x80 (0b00000001 -> 0b10000000).
