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I've tested this in Python 2.7 since I don't have Python 2.6 installed, but I really can't imagine this is valid in Python 2.6, since you can't use print in a lambda expression. – wovano Commented Nov 21, 2021 at 11:40
May 11, 2022 · Since a for loop is a statement (as is print, in Python 2.x), you cannot include it in a lambda expression. Instead, you need to use the write method on sys.stdout along with the join method. x = lambda x: sys.stdout.write("\n".join(x) + "\n") answered May 27, 2014 at 18:15. chepner. 527k 76 580 729.
Mar 8, 2011 · Also lambda can be used in an expression directly, while def is a statement. def f(x, y): return x + y Would give you almost the same result as. f = lambda x, y: x + y And you can use it directly in an expression. g(5, 6, helper=lambda x, y: x + y) which with def would be less concise
The first one. f = lambda x: x*x. [f(x) for x in range(10)] runs f() for each value in the range so it does f(x) for each value. the second one. [lambda x: x*x for x in range(10)] runs the lambda for each value in the list, so it generates all of those functions. answered May 20, 2011 at 18:42.
Because a lambda is (conceptually) the same as a function, just written inline. Your example is equivalent to . def f(x, y) : return x + y just without binding it to a name like f. Also how do you make it return multiple arguments? The same way like with a function. Preferably, you return a tuple: lambda x, y: (x+y, x-y)
That is slower than accessing a local variable and in Python 2.x the list comprehension only accesses local variables. If you are using Python 3.x the list comprehension runs in a separate function so it will also be accessing value through a closure and this difference won't apply.
Currently, in Python, a function's parameters and return types can be type hinted as follows: def func(var1: str, var2: str) -> int: return var1.index(var2) Which indicates that the function takes two strings, and returns an integer. However, this syntax is highly confusing with lambdas, which look like: func = lambda var1, var2: var1.index ...
Apr 3, 2015 · The only thing lambda is good for is allowing you to create anonymous functions and use them in an expression (as opposed to a statement). If you immediately assign the lambda to a variable, it's no longer anonymous, and it's used in a statement, so you're just making your code less readable for no reason.
May 14, 2009 · Python also has a notion of an expression statement, which allows an expression to be used when the grammar expects a statement, but that's not the case here. – chepner Commented Apr 24, 2022 at 12:32
Nov 13, 2014 · Lambda expression with lists as arguments. 0. Actual parameters in Python lambda expressions. 5.
