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Since Mysql doesn't support INTERSECT, you may have 2 alternatives: inner join and in. This is a solution with in: SELECT records.id FROM records, data. WHERE data.id = records.firstname AND data.value = "john". AND records.id in (SELECT records.id FROM records, data.
Aug 4, 2016 · It is more effective, because with the INNER JOIN solution, MySQL will look up for the results of the first query, then for each row, look up for the result in the second query. With the UNION ALL-GROUP BY solution, it will query results of the first query, results of the second query, then group the results all together at once.
Jan 15, 2016 · to get the intersection of table1 and table2: SELECT * FROM table1, table2 WHERE table1.pk=table2.pk; edited Dec 29, 2009 at 15:37. answered Dec 29, 2009 at 14:16. Stephen Wuebker.
It unnests the two json arrays into two temp tables, and return the intersection by inner join on the same values. But when the input array contains same elements (not a set), the result may be not as expected.
Jan 5, 2010 · Nice solution! However I found that in MySQL you need to use DATEDIFF instead of the minus operator -. SELECT o.orderStart, o.orderEnd, s.startDate, s.endDate. , GREATEST(LEAST(orderEnd, endDate) - GREATEST(orderStart, startDate), 0)>0 as overlaps.
Mar 4, 2014 · If you have id the query is very simple: SELECT ID FROM UP26rotordowntime WHERE (Year>=2013) AND (Week >=01) ) SELECT ID FROM UP26rotordowntime WHERE (Year<=2014) AND (Week <=14)) This should return you the intersect you need. Sorry my mistake, you should use OR instead AND. See my edited answer.
Jul 26, 2012 · 1. You get the intersection from an inner join: SELECT a.data FROM a, b WHERE a.data = b.data. To decide whether b is a subset of a, you can do. SELECT b.data FROM b LEFT JOIN a ON a.data = b.data WHERE a.data IS NULL. This will compute the difference: all values from b which are not contained in a.
Aug 17, 2010 · I need to intersect two tables based on a column,in both tables. Here's my code snippet : SELECT b.VisitID, b.CarrierName, b.PhoneNum, b.PatientName, b.SubscriberID ...
Oct 20, 2012 · I'm currently working on the following homework: I'm requested to specify the tuples given: (T1 - T2) union (T2 - T1) Union (T1 intersect T2). Now I know that MySQL uses the, either join for the minus operator, I'm able to process each minus in their own way like: I can also do this for the T2 - T1 but I'm lost when it comes to doing it all in ...
Feb 27, 2016 · 4. Following query will do .. ( SELECT id_user FROM Rating Where id_movie=3); You should be careful about NULLs with this syntax. Depending on each subquery result size and order (A and id_user in B or B and id_user in A), mysql server can take a really long time to give you a result.
