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exit_if=True # and then exit the outer if block. if some condition and not exit_if: # if and only if exit_if wasn't set we want to execute the following code. # keep doing something. if condition_b: # do something. exit_if=True # and then exit the outer if block. if some condition and not exit_if: # keep doing something.
9. Python does not allow empty blocks, unlike many other languages (since it doesn't use braces to indicate a block). The pass keyword must be used any time you want to have an empty block (including in if/else statements and methods). For example, if 3 > 0: print('3 greater then 0') else: pass. Or an empty method:
That's more specifically a ternary operator expression than an if-then, here's the python syntax. value_when_true if condition else value_when_false. Better Example: (thanks Mr. Burns) 'Yes' if fruit == 'Apple' else 'No'. Now with assignment and contrast with if syntax. fruit = 'Apple'. isApple = True if fruit == 'Apple' else False.
Mar 5, 2013 · python 3 replaced python 2's print statement with a function thus the required parentheses, and if you've going to so that you might as well just use sys.stdout.write – Dan D. Commented Aug 26, 2010 at 14:07
is indented to the wrong level; that makes the else: that follows an independent statement, which is syntactically wrong. Probably you meant that print statement to follow the else and be indented one level.
Dec 31, 2013 · for pathitem in path: for item in actual: if pathitem == item: break. else: return False. return True. What makes the use of for / else so great here is the elegance of avoiding juggling a confusing boolean around. Without else, but hoping to achieve the same amount of short-circuiting, it might be written like so:
Here we have one condition. Example 1. Condition: only even numbers will be added to new_list. new_list = [expression for item in iterable if condition == True] new_list = [x for x in range(1, 10) if x % 2 == 0] > [2, 4, 6, 8] Example 2. Condition: only even numbers that are multiple of 3 will be added to new_list.
number = raw_input("> ") if number in range(1, 5): print "You entered a number in the range of 1 to 5". elif number in range(6, 10): print "You entered a number in the range of 6 to 10". else: print "Your number wasn't in the correct range". I find if I put a number between 1 to 10 it always falls to the else statement.
Jun 18, 2013 · Can you sort the things you are running your if/else... chain on, such that all the elements that one of the conditions will match for are at one end, and all the rest are at the other?
elif and else must immediately follow the end of the if block, or Python will assume that the block has closed without them. if 1: pass <--- this line must be indented at the same level as the `pass` else: pass In your code, the interpreter finishes the if block when the indentation, so the elif and the else aren't associated with it. They are ...