Search results
We have unit of mass as Kg dimensions are [M 1] [L 0] [T 0] unit of acceleration as m / s 2 dimensionally expressed as [M 0] [L 1] [T − 2] hence we have unit of force as K g × m / s 2.
The formula for frictional force is given by. Frictional force = Coefficient of friction x Normal force. The dimensional formula of frictional force can be derived as follows: Frictional force = [M^1L^1T^-2] Coefficient of friction = [Dimensionless] Normal force = [M^1L^1T^-2] Substituting the dimensions of coefficient of friction and normal ...
The dimensional formula for impulse is same as the dimensional formula for(a) Momentum(b) Force(c) Rate of change of momentum(d) Torque. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:dimensional formula for electromotive force is same as that for.
Coefficient of viscosity (η)= Fr/Av where F = tangential force, r = distance between the layers , v = velocity. Dimensional Formula of Force = M 1 L 1 T -2 Dimensional Formula of Area= M 0 L 2 T 0
In the equation P = RT V −beaV RTV = volume,P = pressure,R = universal gas constant, and T = temperatureThe dimensional formula of a is same as that of. View Solution. Q 5.
In a fluid may be a gas or a liquid, pressure increases with depth. Learn the buoyancy formula here. Buoyancy Formula What is Buoyancy? Not only does the buoyant force create an upward lift on an object in a fluid, but it is also equal to the weight of the fluid displaced by that object. This was discovered by Archimedes during the 3rd century B.C.
Suppose speed of light (c), force (F) and kinetic energy (K) are taken as the fundamental units, then the dimensional formula for mass will be: View Solution Q 4
In the following dimensionally consistent equation F = X L i n e a r D e n s i t y + Y, where F is the force, the dimensional formula for X and Y are given as: M 2 L 0 T − 2, M L T − 2; M L T − 2, M L 2 T − 2; M 2 L − 2 T − 2, M L T − 2; M 0 L 0 T 0, M L 0 T 0
Let [∈ 0] denote the dimensional formula of the permittivity of the vacuum and [μ 0] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current, then: Given F = 1 4 π ∈ 0 . q 1 q 2 r 2 , where q 1 and q 2 are charges and r is the distance.
The centripetal force F acting on a particle moving uniformly in a circle may depend upon mass (m), velocity (v) and radius (r) of the circle. Derive the formula for F using the method of dimensions. F = m v 2 r (where k = 1) F = m v 2 × r (where k = 1) F = m v 3 × r (where k = 1) F = m v 3 r (where k = 1)
