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The angular momentum as electron is a given orbital is calculated using, Orbital angular momentum = √ l (l + 1) h 2 π. Now for d-electron, l=2
The angular momentum of the electron in the nth orbit= n h 2 π where orbit number = n = 4 (Given) Angular momentum of the electron in the fourth orbit= 4 h 2 π = 2 h π
The angular momentum of an electron in 2s orbital is: View Solution. Q 5. The orbital angular momentum of an electron is √3 h π. Which of the following may be a permissible value of angular momentum of an electon revolving in an unknown Bohr's orbit?
The angular momentum of an electron in the hydrogen atom is 3 h 2 ...
The total energy of an electron in an atom in an orbit is − 3. 4 e V. Its kinetic and potential energies are, respectively Its kinetic and potential energies are, respectively View Solution
The spin angular momentum of electron S = 3 h 4 π. Was this answer helpful? 0. Similar Questions.
The angular momentum of an electron in a given orbit is J, its kinetic energy will be: View Solution. Q2.
A : Angular momentum of an electron in a hydrogen atom is quantized. R : In an atom only those orbits are permitted in which angular momentum of the electron is a natural number multiple of h 2 π View Solution
When an electron in hydrogen atom is excited, from its 4 t h to 5 t h stationary orbit, the change in angular momentum of electron is (Planck’s constant: h = 6.6 × 10 − 34 J − s) View Solution Q 3
The orbital angular momentum for an electron revolving in an orbit is given by √ l (l + 1) h 2 π. Determine this momentum for an s - electron. Determine this momentum for an s - electron. View Solution
