Search results
May 29, 2013 · Here is a fiddle demonstrating the correct behavior. If you just want to validate that the password has at least one letter and at least one number, you can check like this: function checkPasswordComplexity(pwd) {. var letter = /[a-zA-Z]/; var number = /[0-9]/; var valid = number.test(pwd) && letter.test(pwd); //match a letter _and_ a number.
Oct 4, 2010 · 249. On Python 3.6 + you should use the secrets module to generate cryptographically safe passwords. Adapted from the documentation: import secrets. import string. alphabet = string.ascii_letters + string.digits. password = ''.join(secrets.choice(alphabet) for i in range(20)) # for a 20-character password.
Sep 3, 2008 · A short and easy solution, but it uses only lowercase and numerics: Random r = new java.util.Random (); String s = Long.toString (r.nextLong () & Long.MAX_VALUE, 36); The size is about 12 digits to base 36 and can't be improved further, that way. Of course you can append multiple instances.
Dec 3, 2016 · onkeyup="alphanumeric(this)" You can pass in the element that the event was bound to using this. Also I changed the event to onkeyup so you can validate the currently typed character. When you are getting the value you can then use that element to get the current value. var mypswd = input.value.trim()
Jul 21, 2015 · I suggest you use a password confirmed to ensure the user typing the correct password. Within the 6 characters, our regex should contain at least 3 of a-z or A-Z and a number and special character. Always test your code in a test environment before moving to production.
Oct 17, 2022 · Will do at least one upper or lower case alphanumeric or underscore. If it can be zero length, then just substitute the + for *: ^[A-Za-z0-9_]*$ If diacritics need to be included (such as cedilla - ç) then you would need to use the word character which does the same as the above, but includes the diacritic characters: ^\w+$ Or ^\w*$
Jul 28, 2009 · Need help with a regex for alphanumeric password, with at least 1 number and character, and the length must be between 8-20 characters. I have this but doesn't seem to be working (it doesn't have length requirements either): ^[A-Za-z0-9]*[A-Za-z][A-Za-z0-9]*$
Oct 20, 2011 · @Sharpzain120: only alphanumeric password means only letters and numbers... Also, in order to force a number and letter, you'll need two separate checks. Your check is only making sure there is at least 1 letter or number. –
for HTML5 validation pattern alphanumeric with space :-. onkeypress="return event.charCode >= 48 && event.charCode <= 57 || event.charCode >= 97 && event.charCode <= 122 || event.charCode >= 65 && event.charCode <= 90 || event.charCode == 32". The question seems to be looking for a validation pattern. Also, please note that keyboard event ...
Jul 30, 2010 · 19. Try this: bool result =. passwordText.Any(c => char.IsLetter(c)) &&. passwordText.Any(c => char.IsDigit(c)) &&. passwordText.Any(c => char.IsSymbol(c)); Though you might want to be a little more specific about what you mean by 'alphabet character', 'number' and 'symbol' because these terms mean different things to different people and it's ...
