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Feb 11, 2016 · y = √ 1 2 = √2 2. To get the sin of π 4 you divide the opposite catet (√2 2) by the hypothenuse ( 1). You'll get √2 2. Answer link. sqrt (2)/2 In the trigonometric circle pi/4 is the bisectrix between 0 and pi/2, where x=y. By the Pythogoras theorem we know that x^2+y^2=1. If you don't know the trigonometric circle, you can see that if ...
Mar 25, 2016 · Apply the trig identity: sin (a + b) = sin a.cos b + sin b.cos a #sin (x + pi/4) = sin (pi/4).cos x + cos (pi/4)sin x =#
Feb 17, 2016 · 1/2 sin (pi/4).sin (pi/4) = (sqrt2/2)(sqrt2/2) = 2/4 = 1/2. How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle?
Apr 13, 2018 · At π 4, we can see that the x -value is √2 2. Therefore, cos(π 4) = √2 2. Hope this helps! sqrt2/2 As you can see in the table above, cos45^@ or cospi/4 radians is the same thing as sqrt2/2 An alternative way is looking at the unit circle: We know that the cosine of an angle is the x-value of a coordinate. At pi/4, we can see that the x ...
Apr 17, 2015 · What is the value of #sin(pi/4)#? Trigonometry Graphing Trigonometric Functions Applications of Radian ...
Apr 20, 2015 · How do you find the exact value for. sin. (. π. 4. ) ? Trigonometry Right Triangles Trigonometric Functions of Any Angle.
Jul 27, 2016 · How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question
Jul 31, 2016 · This shows that, 13pi/4=3pi+pi/4 lies in the Third Quadrant in which, sin is -ve. Finally, sin(3pi+pi/4 ...
May 1, 2018 · sin(7*pi/4) = -sqrt2/2 pi in general equals to 3.142 in radian form or 180 degrees since 2pi = 360 degrees ...
Dec 14, 2016 · Take the square root of both sides: x = ± √2 2. If each side = √2 2, then both the sine and cosine are equal to that value since the hypotenuse is 1. Answer link. pi means 180 ° Hence pi/4 means 180/4 which is 45 ° . 45 ° is a special triangle where the measurements are Now, you can find the sine, cosine and tangent without a calculator!
