Search results
Feb 2, 2015 · Below is the solution written for above problem that performs hailstone sequence: count = 1. """Print the terms of the 'hailstone sequence' from n to 1.""". assert n > 0. print(n) if n > 1: if n % 2 == 0: count += hailstone(n / 2) else:
Oct 28, 2021 · All sequences of that length are then generated and the code eliminates the ones which violate any of the constraints. Finally, the user is presented with a list of valid sequences as well as a breakdown of valid digits for each position in the sequence.
Mar 3, 2021 · Collect tuples of the ranges at which the sequences are found. Armed with Python 3.9, this is my code: -> list[tuple[int, int, int, int]]: """. Returns all top-level matches of opening sequences to closing sequences. Each match is represented as a 4-tuple of the range that the opening and closing sequences span.
Aug 10, 2016 · Pseudocode of algorithm: Start off with a random sequence A and find other sequences containing A[0-X]. Go through the list of sequences one by one. If a sequence B contains substring A[0-X] Check for an overlap on the left end of sequence B. if there's an overlap combine the sequences. Re-assign new A[0-X]
Jun 28, 2021 · import re def check_and_clean_sequence(sequence, alphabet): """ Function to check and clean up all ambiguous bases in a sequence. Ambigous bases are bases that are not in the sequence alphabet, ie. 'ACGT' for DNA sequences. Inputs: sequence - a string representing a DNA sequence.
Feb 4, 2019 · This is the code that I came up with: import numpy as np. def extract_subsequences(seq): def split_sequence(seq): for i in np.arange(1, len(seq)): if seq[i] != seq[i - 1] + 1: break. if i < len(seq) - 1: return seq[:i], seq[i:]
Jul 9, 2022 · to enter a 'n' value and get the value based on the nth term. If 'sequence' is set to False, you can input a list with an nth term instead of. a sequence. The list needs to be written the same way as self.calc is if. sequence is set to false so [[3, 2], [1, 1], [2, 0]] would be 3n^2 + n + 2 for example.
Dec 6, 2016 · Here is a code I would need to make far faster: it is made to analyse more than 3000 DNA sequences of more than 100 000 characters each. The matter is I have to compare it by pair, so that would be
Dec 14, 2016 · I recently applied for a job as a Python coder but was rejected. This was the problem: Write a python code to check if an array has a sequence (1,3,4) Assuming they were looking for expert Pyt...
Nov 4, 2019 · I've written a small script to calculate Collatz sequences. For background, read here about the Collatz conjecture . Largest number I've tried so far in my implementation is 93571393692802302 (which wikipedia claims is the number requiring most steps below 10e17), which needs 2091 steps.
