Search results
Jul 24, 2012 · Finally, 1 is subtracted from this remaining value, resulting in -1 if the year is a leap year, and either 0, 1, or 2 if it is not. This value is compared against 0 with the less-than operator. If the year is a leap year this will result in True (or 1, if used in C), otherwise it will return False (or 0, if used in C).
Sep 15, 2020 · This is getting a little confusing because in fact you don't have to check if the year you input is a leap year or not, you just have to increment the input by 1 until you find a year that matches the conditions of being a leap year. Here's my code for the same exercise. I hope it helps :)
May 10, 2020 · 0. 1900/4= 475 => input_year%4 == 0 is True => for your code 1900 is a leap year. 1901/4 = 475,25 => input_year%4 == 0 is false => for your code 1901 is not a leap year. answered May 10, 2020 at 20:43.
Jun 8, 2019 · A leap year contains a leap day. In the Gregorian calendar, three conditions are used to identify leap years: The year can be evenly divided by 4, is a leap year, unless: The year can be evenly divided by 100, it is NOT a leap year, unless: The year is also evenly divisible by 400. Then it is a leap years. Solution is the below Python Code.
Sep 23, 2013 · The code is working just fine. This was the following session: Enter starting year: 2008 Enter ending year: 2032 Leap years between 2008 and 2032 2008 2012 2016 2020 2024 2028 2032
Nov 13, 2022 · Handling the exceptions first yields clearer code. def is_leap(year): if year % 400 == 0: return True # an exception to the century rule if year % 100 == 0: return False # centuries aren't leap years return year % 4 == 0
Write a program which works out the leap years between two years given by the user. The program should list 10 leap years per line, with commas between each year listed and a full stop at the end, as in the following example input/output: Enter start year: 1000. Enter end year: 1200. Here is a list of leap years between 1000 and 1200:
Jul 7, 2015 · I have to write a program where I enter a number and the program replies whether the number is a leap year or not. I'm new to python so I am unsure of where to start. So far, I know that a leap year is any number divisible by 4, but not by 100 (unless it is also divisible by 400).
May 11, 2022 · We can save if it is a leap year, change our mind if it is divisible by 100, and then change our mind again if it is divisible by 400. def is_leap(year): leap = False. # The year can be evenly divided by 4, is a leap year. if year%4 == 0: leap = True. # Unless the year can be evenly divided by 100.
Dec 11, 2012 · I have a program where the user enters a date and then compares it to another date to see which one comes first. How would I go about writing a code where the user inputs Feb 29 and the program re...
