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Aug 6, 2009 · to get the intersection of table1 and table2: SELECT * FROM table1, table2 WHERE table1.pk=table2.pk; edited Dec 29, 2009 at 15:37. answered Dec 29, 2009 at 14:16. Stephen Wuebker.
Since Mysql doesn't support INTERSECT, you may have 2 alternatives: inner join and in. This is a solution with in: SELECT records.id FROM records, data. WHERE data.id = records.firstname AND data.value = "john". AND records.id in (SELECT records.id FROM records, data.
Jul 16, 2010 · 24. Looking for the easist/most scalable way to do a set "difference" in SQL Server see below. If you can't tell from the picture i am looking for everything that is not in the intersection. I have seen one way to do it: select * from (. (select 'test1' as a, 1 as b) union all. (select 'test2' as a , 2 as b union all select 'test1' as a , 1 as b )
Jun 2, 2010 · 0. Use INTERSECT statement only if u want to find common line produce by the individual querys. You're statement: " SELECT * FROM results,Types WHERE results.a=Types.b. INTERSECT SELECT * FROM results,Types WHERE results.c=Types.b ". don't match the criteria needed for the joint to work."WHERE" clause is creating the problem.
4. There is no reason to use RIGHT JOIN. For most people, it is simply more confusing than LEFT JOIN for two reasons. First, the FROM clause is read "left to right". A LEFT JOIN keeps all rows in the first table in the clause. The RIGHT JOIN in the not-yet-seen last table. Second, the FROM clause is parsed left-to-right, which introduces some ...
Apr 27, 2015 · First, you want to COUNT the number of rows per InvoiceID that matched the criteria Product = 'Apple' or 'Banana'. Then do a SELF-JOIN and filter the rows such that the COUNT must be >= 2, or the number of Product s in your critera. SQL Fiddle. SELECT sd.*.
Nov 28, 2008 · The short (ish) answer is: given two date intervals A and B with components .start and .end and the constraint .start <= .end, then two intervals overlap if: A.end >= B.start AND A.start <= B.end. You can tune the use of >= vs > and <= vs < to meet your requirements for degree of overlap. ErikE comments:
Jun 7, 2016 · For example, when one table has the ID 1, 2, 7, 8, while another table has the ID 7 and 8 only, the way we get the intersection is: select * from t1, t2 where t1.ID = t2.ID to get the two records of "7 and 8". So it is actually an intersection. So we have the "Intersection" of 2 tables. Compare this with the "Union" operation on 2 tables.
Feb 10, 2017 · 2. Given the tables A and B, you are looking for (A U B) - (A & B). In other words, you need A union B minus their intersection. Remember A and B must be union-compatible for this query to work. I would do: union. select * from B. intersect. select * from B.
Feb 27, 2016 · How about: SELECT r2.id_user. FROM Rating AS r2. JOIN. Rating AS r3. ON r3.id_user = r2.id_user. AND r2.id_movie=2. AND r3.id_movie=3; The idea here is that you want to join a row in Rating with another row in Rating, for which the same user has seen movies 2 and 3.
