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May 24, 2009 · SELECT DATEDIFF('2012-04-30', '2009-05-24') `total_days`; return 1072 days, which is roughly 2 Years, 11 Months, 12 Days. Please do not answer with PHP code, I already try it. Here is the code. The function below uses PHP >= 5.3 functions and convert days to years, months and days.
The problem is this code is returning the date in days and I would like to receive in years. Example: [deleted_at] 2018-06-17 23:59:08 - [birth_date] 1966-01-25. Is returning: 52 days 09:27:43.101984942. Should return 52 years, x months, y days, or even just 52 years. Is there an easy way to do that?
Mar 20, 2018 · If you need to convert total days to years, months, and days (within in month), use the following code: The output in three separate columns is: The following code "combines" the results into one column: CAST(FLOOR(DATEDIFF(DD, [cA].[Date2], GETDATE()) % 30.4375) AS varchar) + ' Days' AS 'Duration'. The output in one column is:
Sep 2, 2021 · Well, converting to months would be dividing the days by 30 (approximately) or multiplying the years by 12. Of course there's a little inaccuracy which comes with this very simple approach, but maybe it's enough for your use-case. –
However, it doesn't feet my needs. I must consider 1 year = 365 days and/or 12 months; and 1 month = 30 days. To transform 3 years, 2 months and 20 days into days, all I need is this formula: (365x3)+(30x2)+20, which is equal to 1175. However, how can I transform days into years, months and days, considering that the amount of days may or may ...
Using dateutil.relativedelta.relativedelta is very efficient here: Except for using .months or .days. because rdelta.months gives you the remaining months after using full years, it doesn't give you the actual difference in months. You should convert years to months if you need to see the difference in months.
Oct 28, 2013 · Based on your comments and the following conditions. 1 year = 365 days. 1 month = 30 days. Then the following code would do the job. DateTime startDate = new DateTime(2010, 1, 1); DateTime endDate = new DateTime(2013, 1, 10); var totalDays = (endDate - startDate).TotalDays;
Jan 13, 2020 · You want to transfer that into one unit: float fraction of years. One way to do this is to convert into just one of the available units and then convert into years. Hence: x = pd.Timedelta('3706 days 10:37:40.303097') x.seconds. >>38260. x.days*24*3600+x.seconds. >>320236660 #Number of seconds in the Timedelta. (x.days*24*3600+x.seconds ...
Feb 27, 2019 · As I said - this gives me the answer in days . 1782 days 00:00:00.000000000 but i want it in years (and fractions of years e.g. 45.5 years). I've tried using the following code to change it to years. Transitions3['AgeAtFirstDial']= pandas.to_datetime(Transitions3['AgeAtFirstDial'], unit="y") but I get this error: ValueError: cannot cast unit y
Aug 21, 2020 · I used lubridate to cast the dates as an interval, as.period to get the time between them as a period, then to get the number of years. interval(t2, t1) %>% as.period() %>% year() or. year(as.period(interval(t2, t1))) Without year, you get "8y 6m 6d 0H 0M 0S" and with year this gives 8 years difference as an integer.
