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Jul 8, 2020 · Then you do num++; and then check while(num<=1000); it's an infinite loop. Maybe you need another counter there. Start your program in a debugger and step line by line through your code. Check the value of num in different lines, especially after }while(num!=0); and in }while(num<=1000);
Nov 7, 2015 · You should need another temporary variable, say div. And, you should finally print temp. Also, an Armstrong number is an n-digit number that is equal to the sum of the nth powers of its digits. So, for 1000, you need to caclculate the 4th power. temp = i; div = i; while(div!=0) rem = div%10; sum = sum + pow(rem,3);
Oct 10, 2016 · As others have suggested Don't change n inside the for loop as your loop depends on the variable n. you have to set b back to 0 for each iteration.
Oct 4, 2014 · (x 1 *10 (n-1))+(x 1 *10 (n-2))...+(x 1 *10 (n-n)) = (x 1) n +(x 2) n...+(x n) n. This means that if the number is 1 digit, the power will be 1. Therefore there are 10 1 digit numbers that are Armstrong numbers: 0 = 0 1; 1 = 1 1; 2 = 2 1; 3 = 3 1; 4 = 4 1; 5 = 5 1; 6 = 6 1; 7 = 7 1; 8 = 8 1; 9 = 9 1; Your code, as written, will not identify any ...
Oct 27, 2016 · I'm trying to print out Armstrong Numbers from 1-10000, and my question is that there are "four 1s" when i compile and run, and I would like to ask which part of coding that I did wrong, and what part of code should be revised if I want only one 1 to be printed out. Other than that, all the others Armstrong Numbers output correctly.
Oct 1, 2021 · How to print Armstrong numbers from 1 to 1000 in Bash ... Print Armstrong numbers between 1 to 1000000 ...
Jan 26, 2019 · In the given number if we calculate the sum of each (digit)^ (number of digits of that number) then the resulting number is same as given number, then it is armstrong. So 1^1 = 1, 2^1 = 2, 3^1 = 3 and so on. For 3 digit number 153 = 1^3 + 5^3 + 3^3. Similarly for 4 digit number for eg : 1634 = 1^4+6^4+3^4+4^4.
Feb 12, 2016 · Generate numbers between the range you want to check for existance of armstrong numbers. for x in range(100,1000): #Get the digits from the number generated as a, b, c. a = x//100. b = (x%100)//10. c = x%10. #now check whether the number is armstrong number or not. #here, a**3 + b**3 + c**3 == abc.
Oct 28, 2016 · How can I print Armstrong numbers between 1 to 1000000? I wrote this code, but it only prints 1 153 370 371 407 numbers. I want to print 1 to 1 million Armstrong numbers.
Nov 10, 2021 · You never reset s and you do not need the final IF statement (unless you are only interested in the Armstrong numbers which equal the original number): declare. n number; s number:=0; r number; len number; m number; begin. for a in 1..500 loop.
