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Solution: We can find the angular momentum by using the formula, and the moment of inertia of a solid disc (ignoring the hole that is present in the middle). The angular momentum will be: L = I ω. L = (12MR2)ω. So, L = 12(0.0200kg)(0.0600m)2(160.0radians/s) L = 0.00576 kg. m2 /s. The angular momentum of this DVD will be 0.00576 kg. m2 /s.
SI Unit of angular momentum kgm2/sAngular momentum =moment of inertia×Angular velocity....(1)Dimensional formula of moment of inertia=M1L2T0Dimensional formula of Angular velocity =M0L0T−1Putting these values in above eq. (1)So dimensional formula of angular momentum =M1L2T−1. Was this answer helpful? State S.I. unit of angular momentum ...
Its SI unit is Nm. The dimension of the torque is ML²T-2. Angular Momentum. Torque and angular momentum are closely related to each other. Angular momentum is the rotational analogue of linear momentum ‘p’ and is denoted by ‘l’. It is a vector product. Angular momentum of the particle is. l = r × p
Angular momentum is given by: L = r×mv. Linear momentum is given by: p = mv. Ratio of angular momentum to the linear momentum is: L p = r ×mv mv = r. Unit of r is meter. Hence, dimension of r is [L1] Therefore, t he dimension of the ratio of angular momentum and linear momentum is: L p =[L1] Was this answer helpful?
The correct option is C angular momentum Planck's constant, symbolized h , relates the energy in one quantum (photon) of electromagnetic radiation to the frequency of that radiation. h = E v = [ M L 2 T − 2 ] [ T − 1 ] = [ M L 2 T − 1 ]
L =r p sinθ, where r is the position and p is momentum. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:dimensional formula for angular momentum.
If E, M, J and G respectively denote energy, mass, angular momentum and universal gravitational constant, the quantity, which has the same dimensions as the dimensions of E J 2 M 5 G 2 is: View Solution
If E, M, J and G respectively denote energy, mass, angular momentum and universal gravitational constant, the quantity, which has the same dimensions as the dimensions of E J 2 M 5 G 2 is: View Solution
Time (T),Velocity (C) and angular momentum (H) are chosen as fundamental quantities instead of mass, length and time. In terms of these, dimension of mass would be: In terms of these, dimension of mass would be:
E, m,l and G denote energy, mass, angular momentum and gravitational constant respectively, then the dimension of El2 m2G2 are. If E,m,J and G denote energy, mass, angular momentum and gravitational constant respectively. Then the dimensions of EJ 2 m5G2 are same as that of.
