Yahoo India Web Search

Search results

  1. The setTimeout() is supposed to trigger another method in the same Class, so the function I am passing it is written as window.setTimeout("this.anotherMethod", 4000). That bring the problem: this references the calling Object, in the case of setTimeout() it is window .

  2. 942. In modern browsers (ie IE11 and beyond), the "setTimeout" receives a third parameter that is sent as parameter to the internal function at the end of the timer. Example: var hello = "Hello World"; setTimeout(alert, 1000, hello); More details at setTimeout () global function - MDN. edited Jan 2 at 1:00.

  3. setTimeout(playNote, delay); Note: For repeated events you can use setInterval() and you can set setInterval() to a variable and use the variable to stop the interval with clearInterval(). You say you use setTimeout() in a for loop. In many situations, it is better to use setTimeout() in a recursive function.

  4. The issue is that setTimeout() causes javascript to use the global scope. Essentially, you're calling the method() class, but not from this. Instead you're just telling setTimeout to use the function method, with no particular scope. To fix this you can wrap the function call in another function call that references the correct variables.

  5. Dec 29, 2010 · setTimeOut sets a timer and executes the given code after that timer timed out. So using your code, if startTime is called once, it is repeated every half second. Btw. I assume the delay of 500 ms is used te work around small deviations in the clock. You will want to update the value of the element every whole second.

  6. Jun 9, 2016 · 1. Yes. There are 2 problems in your code: The setTimeout function accept a function as the first argument, but in your code, myfunc03(i) returns nothing. The while loop won't meet you needs, instead, you have to use recursive function. Since the second function should be invoked after the first timeout is fired.

  7. Jan 12, 2017 · setTimeout(function(){alert("Hello " + a)}, 2000); a = "Stack Overflow"; But if you run that code you will notice that after 2 seconds the popup will say 'Hello Stack Overflow'. This is because the value of the variable a has changed in those two seconds. To get it to say 'Hello world' after two seconds, you need to use the following code ...

  8. Aug 16, 2013 · When the above methods are to get the timeout, they must run the following steps: Let timeout be the second argument to the method, or zero if the argument was omitted. Apply the ToString () abstract operation to timeout, and let timeout be the result. [ECMA262] Apply the ToNumber () abstract operation to timeout, and let timeout be the result.

  9. Apr 30, 2019 · var header = yellowTitles[i]; var timer = i*500; var yellowBar = setTimeout(animeYellowBar,timer); function animeYellowBar(){. header.style.left= "0"; PLEASE use the code button in the toolbar to format the code. You're overriding my edit over and over again.

  10. Oct 11, 2014 · Do not use Thread.sleep as it will freeze your main thread, and not simulate setTimeout from JS. You need to create and start a new background thread to run your code without stoping the execution of the main thread.