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Nov 20, 2016 · In your case, you want to split a string when there is a "-". You can simply do as follows: String str = "004-034556"; String split[] = StringUtils.split(str,"-"); Output: 004. 034556. Assume that if - does not exists in your string, it returns the given string, and you will not get any exception.
After some research, I found that indexOf and substring are quite efficient but the examples only have single delimiters or results are returning only a single word/element. Sample code using indexOf and substring: String s = "quick,brown,fox,jumps,over,the,lazy,dog"; int from = s.indexOf(','); int to = s.indexOf(',', from+1);
Dec 2, 2016 · String input = "dog,cat,bird"; Stream<String> stream = Arrays.stream(input.split( "," )); stream.forEach(System.out::println); Stream.of / String.split Stream.of is a varargs method which just happens to accept an array, due to the fact that varargs methods are implemented via arrays and there were compatibility concerns when varargs were introduced to Java and existing methods retrofitted to accept variable arguments.
Feb 12, 2013 · 965. You need to escape the dot if you want to split on a literal dot: String extensionRemoved = filename.split("\\.")[0]; Otherwise you are splitting on the regex ., which means "any character". Note the double backslash needed to create a single backslash in the regex.
Oct 5, 2016 · 15. Use Stringutils.split() to split the string by whites paces. For example StringUtils.split("Hello World") returns "Hello" and "World"; In order to solve the mentioned case we use split method like this. String split[]= StringUtils.split("Hello I'm your String"); when we print the split array the output will be :
Jan 19, 2013 · Trailing empty strings are therefore not included in the resulting array. If you want those trailing empty strings included, you need to use String.split(String regex, int limit) with a negative value for the second parameter (limit): String[] array = values.split("\\|", -1); edited Nov 14, 2014 at 8:38. answered Jan 19, 2013 at 13:00.
455. You need. test.split("\\|"); split uses regular expression and in regex | is a metacharacter representing the OR operator. You need to escape that character using \ (written in String as "\\" since \ is also a metacharacter in String literals and require another \ to escape it). You can also use.
The same thing has happened with the I am preparing for OCPJP String, it has been split, and the points matched by your regex are not in any of the returned values. And because most of the letters in that String are followed by another letter, you end up with a load of Strings of length zero, only the white space characters are preserved.
Jan 31, 2017 · String[] result = {"foo boo", "faa baa", "fii bii"}; This should work: String[] s = attributes.trim().split("[,]"); As answered by @Raman Sahasi: before you split your string, you can trim the trailing and leading spaces. I've used the delimiter , as it was your only delimiter in your string.
private void getId(String pdfName){ String[] tokens = StringUtils.split(pdfName, "-."); It'll split on any of the specified separators, as opposed to StringUtils.splitByWholeSeparator(str, separator) which uses the complete string as a separator
