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May 31, 2012 · Both replace () and replaceAll () accepts two arguments and replaces all occurrences of the first substring (first argument) in a string with the second substring (second argument). replace () accepts a pair of char or charsequence and replaceAll () accepts a pair of regex. It is not true that replace () works faster than replaceAll () since ...
May 27, 2017 · From Java Doc, "Returns a string whose value is this string, with any leading and trailing whitespace removed." System.out.println(" D ev Dum my ".trim()); "D ev Dum my" replace(), replaceAll() Replaces all the empty strings in the word,
Nov 26, 2009 · 3. If you want to also allow alphanumeric characters which don't belong to the ascii characters set, like for instance german umlaut's, you can consider using the following solution: String value = "your value"; // this could be placed as a static final constant, so the compiling is only done once.
Or try the replaceAll method, as recommended in this answer: str = str.replaceAll('abc', ''); or: var search = 'abc'; str = str.replaceAll(search, ''); EDIT: Clarification about replaceAll availability. The replaceAll method is added to String's prototype. This means it will be available for all string objects/literals. Example:
Mar 24, 2012 · 79. Don't use regex!. You only need a plain-text match to replace "\n". Use replace() to replace a literal string with another: string = string.replace("\n", " --linebreak-- "); Note that replace() still replaces all occurrences, as does replaceAll() - the difference is that replaceAll() uses regex to search.
May 4, 2021 · If you also do not need "-" in String you can do like this: String phoneNumberstr = "Tel: 00971-55 7890 999"; String numberRefined = phoneNumberstr.replaceAll("[^0-9]", ""); Result: 0097557890999. edited Jul 6, 2021 at 13:48.
Jul 7, 2009 · Why use a regular expression at all? If you don't need a pattern, just use replace: String output = input.replace("N/A", "0"); answered Jul 7, 2009 at 13:43. Jon Skeet. 1.5m 885 9.3k 9.3k. The Java API describes the first argument as a regular expression. Hence the form of the question. – SteveT.
Mar 28, 2011 · The easiest way to do this is by using the org.apache.commons.lang3.StringUtils class of commons-lang3 library such as " commons-lang3-3.1.jar " for example. Use the static method " StringUtils.deleteWhitespace(String str) " on your input string & it will return you a string after removing all the white spaces from it.
If your strings are coming from a Windows based source such as an aspx based server, this solution does work: rawText.replaceAll("(\\\\r\\\\n|\\\\n)", "<br />"); Seems to be a weird character set issue as the double back-slashes are being interpreted as single slash escape characters. Hence the need for the quadruple slashes above.
Rythm a java template engine now released with an new feature called String interpolation mode which allows you do something like: String result = Rythm.render("@name is inviting you", "Diana"); The above case shows you can pass argument to template by position.
