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Magnetic moment. Answer: A. Self-inductance is that phenomenon in which charge in electric current in a coil produces an induced emf in the coil itself. Q2. Two coils A and B have L= 2×10 -2 Henry. If the current in the primary is i = 5 sin 10πθ then maximum value of emf induced in coil B is: Π volt.
Unlock Full Access! 40. The self inductance of a toroid is :- MoN22 (2) HoNrr (2) 2R 2R (3) (4) HyNr. Was this answer helpful? If the current in the toroidal solenoid increases uniformly from zero to 6.0A in 3.0μs.Self inductance of the toroidal solenoid is 40μH. The magnitude of self-induced emf is.
Self-inductance of a coil is defined as the phenomenon due to which an emf is induced in a coil when the magnetic flux of coil , linked with the coil changes or current in coil changes . Its S.I. unit is H e n r y (H).
It is clear that self inductance of solenoid depends upon the following factors: (1) On relative permeability of material inside the solenoid: If a soft iron core placed inside the solenoid, the magnetic flux linked with the solenoid increased hence, self inductance of the solenoid will also increases. (2) On total number of turns in solenoid ...
Click here:point_up_2:to get an answer to your question :writing_hand:dimensional formula of self inductance is
The self-inductance of an air core solenoid of 100 turns is 1 m H. The self-inductance of another Solenoid of 50 turns (with the same length and cross-sectional area) with a core having relative permeability 500 is
Inductance is the electromotive force generated to oppose the change in current at a particular time duration. Formula According to Faraday’s Law. Electromotive force = -L ΔI Δt. Unit of Inductance = Volt×second Ampere. Lenz law E = −NdΦB dt. Lenz’s law gives the direction of the electromotive force.
Click here:point_up_2:to get an answer to your question :writing_hand:the dimensions of self inductance are
L refers to the inductance. Φ is the Magnetic flux. N refers to the number of coil turns. I is the intensity of the current. Solved Question on Inductance Formula. Question- An inductor coil contains 550 turns of copper wire which generates a magnetic flux of 20 Wb when it passes a direct current of 5 amps. Find out the self-inductance of the ...
take a solenoid having a large number of insulated wire wound over over a soft iron core . such a solenoid is called a choke coil. connect the solenoid in series with battery . a eheostat and a tapping key . connect a 6 v bulb in parallel with the solenoid . press the tapping key and adjust the current with the help pf rheostat so that the bulb just glows faintly .
