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  1. Apr 7, 2023 · might be better. If you need all three parts, this will do: "(\\D+)(\\d+)(.*)" EDIT The Expressions given by Allain and Jack suggest that you need to specify some subset of non-digits in order to capture digits. If you tell the regex engine you're looking for \d then it's going to ignore everything before the digits.

  2. Nov 28, 2012 · To match the strings one OR other, use: or if you don't want to store the matches, just simply. To be Java specific, this article is very good at explaining the subject. You will have to use your patterns this way: String matchedString = myStrin.substring(matcher.start(),matcher.end());

  3. The Java API for regular expressions states that \s will match whitespace. So the regex \\s\\s should match two spaces. Pattern whitespace = Pattern.compile("\\s\\s"); matcher = whitespace.matcher(modLine); while (matcher.find()) matcher.replaceAll(" "); The aim of this is to replace all instances of two consecutive whitespace with a single space.

  4. Feb 2, 2016 · Combining what everyone said, I propose the following, to keep the list of characters special to RegExp clearly listed in their own String, and to avoid having to try to visually parse thousands of "\\"'s. This seems to work pretty well for me: Matcher m = reCharsREP.matcher( s); return m.replaceAll( "\\\\$0");

  5. Jun 16, 2016 · The head-ache-y part of regular expressions in Java is that you need to double escape any literal characters with \\, since you want a literal backslash character to appear in the string that you're passing to the regex compiler.

  6. Since Java 9. As of this version, you can use a new method Matcher::results with no args that is able to comfortably return Stream<MatchResult> where MatchResult represents the result of a match operation and offers to read matched groups and more (this class is known since Java 1.5).

  7. Aug 2, 2011 · 17. ^ means "Match the start of the string" (more exactly, the position before the first character in the string, so it does not match an actual character). $ means "Match the end of the string" (the position after the last character in the string). Both are called anchors and ensure that the entire string is matched instead of just a substring.

  8. Oct 21, 2011 · Writing a simple regex, but I've never been very good at this. What I'm trying to do is check a string (filename) to make sure it only contains a-z, A-Z, 0-9 or the special characters underscore (_) period (.) or dash (-). Here's what I have. return false; return true; This appears to work, but does not look very elegant to me.

  9. Oct 25, 2013 · I am trying to implement an if statement to accept any word consisting with any of the letters a-k (both upper and lower case) in Java. My input is a String. I guess it would be something like: if...

  10. Feb 3, 2017 · 129. Regular expressions in Java are compiled into an internal data structure. This compilation is the time-consuming process. Each time you invoke the method String.matches(String regex), the specified regular expression is compiled again. So you should compile your regular expression only once and reuse it: