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Minimum Window Substring - Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, return the empty string "".
class Solution { public: string minWindow(string s, string t) { vector<int> count(128); int required = t.length(); int bestLeft = -1; int minLength = s.length() + 1; for (const char c : t) ++count[c]; for (int l = 0, r = 0; r < s.length(); ++r) { if (--count[s[r]] >= 0) --required; while (required == 0) { if (r - l + 1 < minLength) { bestLeft = ...
Mar 4, 2024 · Smallest window in a String containing all characters of other String using Two Pointers and Hashing: The idea is to use the two pointer approach on the hash array of pattern string and then find the minimum window by eliminating characters from the start of the window. Follow the steps below to solve the problem:
Problem Description. The problem requires us to find the smallest segment (substring) from string s that contains all the characters from string t, including duplicates. This segment or substring must be minimized in length and must contain each character from t at least as many times as it appears in t.
Given strings str1 and str2, find the minimum (contiguous) substring W of str1, so that str2 is a subsequence of W. If there is no such window in str1 that covers all characters in str2, return the empty string "".
Jul 31, 2023 · The Minimum Window Substring is a classical problem that tests one’s understanding of strings, sliding windows, and the ability to write efficient algorithms. We are given two strings, s and t,...
Example 1: Input: s ="ADOBECODEBANC", t ="ABC"Output: "BANC"Explanation: The smallest substring of s that includes all the characters of t is "BANC". Example 2: Input: s ="a", t ="a"Output: "a"t.
Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, return the empty string "". The testcases will be generated such that the answer is unique. Constraints: m == s.length. n == t.length.
Minimum Window Substring. Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O (n). Example: Input: S = "ADOBECODEBANC", T = "ABC". Output: "BANC". Note: If there is no such window in S that covers all characters in T, return the empty string "" .
Given two strings S and P. Find the smallest window in the string S consisting of all the characters (including duplicates) of the string P. Return "-1" in case there is no such window present. In case there are multiple such windows of same length, return the one with the least starting index.
