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  1. Dictionary
    distinct
    /dɪˈstɪŋ(k)t/

    adjective

    More definitions, origin and scrabble points

  2. To do this, you need to use an aggregate function to sort on, and use a GROUP BY to make the DISTINCT work. Try something like this: SELECT DISTINCT Category, MAX(CreationDate) FROM MonitoringJob. GROUP BY Category. ORDER BY MAX(CreationDate) DESC, Category. edited Dec 28, 2017 at 15:48.

  3. Dec 27, 2010 · 4. Entity-Framework Select Distinct Name: Suppose if you are using Views in which you are using multiple tables and you want to apply distinct in that case first you have to store value in variable & then you can apply Distinct on that variable like this one.... public List<Item_Img_Sal_VIEW> GetItemDescription(int ItemNo)

  4. Mar 31, 2010 · Interesting scenario. As you found, SELECT DISTINCT(a), b, c. is equivalent to: SELECT DISTINCT (a), b, c. is equivalent to: SELECT DISTINCT a, b, c. i.e. the parentheses are treated as expression grouping parentheses. Interestingly, a very similar issue occurs in VB6/VBScript where (for Function (byref x)) Function (x), Function x and Call ...

  5. Oct 15, 2012 · I want to get the unique values from the following list: ['nowplaying', 'PBS', 'PBS', 'nowplaying', 'job', 'debate', 'thenandnow'] The output which I require is ...

  6. Jun 19, 2016 · 11. DISTINCT (or DISTINCTROW) is not a function; it is an option of the SELECT statement that tells MySQL to strip duplicate rows from the resultset generated by the query. By default it returns all the generated rows, including the duplicates. It can also be used together with COUNT() aggregate function (as COUNT(DISTINCT expr)) and it has the ...

  7. Jan 29, 2009 · 98. Starting with .NET 6, there is new solution using the new DistinctBy() extension in Linq, so we can do: var distinctPersonsById = personList.DistinctBy(x => x.Id); The signature of the DistinctBy method: // Returns distinct elements from a sequence according to a specified. // key selector function.

  8. Having done so, you can also write your own extension method that takes a delegate. Cool! If someone missed it you can do: source.DistinctBy (x => new { x.A, x.B }); TIdentity should have a IEquatable<TIdentity> constraint, and therefore, use the identitySelector(x).Equals(identitySelector(y)) instead.

  9. May 16, 2014 · 3. @DanielEarwicker this question is about "distinct by property". It would require the stream to be sorted by the same property, to be able to take advantage of it. First, the OP did never state that the stream is sorted at all. Second, streams are not able to detect whether they are sorted by a certain property.

  10. Nov 30, 2010 · var distinct = items.GroupBy(x => x.ID).Select(x => x.First()); where ID is the property that determines if two objects are semantically equivalent. From the confusion here (including that of myself), the default implementation of Distinct() seems to be a little convoluted.

  11. Oct 16, 2022 · The standard way to define distinct opaque types is to use incomplete structure declarations. A header used throughout the program simply declares struct foo; struct bar; and so on without saying anything about their contents. Pointers to these are distinct types and may be used by code with no knowledge of the structure contents.