Search results
4 days ago · Given a list of numbers, write a Python program to print all odd numbers in the given list. Example: Input: list1 = [2, 7, 5, 64, 14] Output: [7, 5] Input: list2 = [12, 14, 95, 3, 73] Output: [95, 3, 73] Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0.
- 6 min
5 days ago · List comprehensions allow you to create a list on the fly in one elegant one-liner. We can implement this in our code as follows: def main (): yell ( " This " , " is " , " CS50 " ) def yell ( * words ): uppercased = [ arg . upper () for arg in words ] print ( * uppercased ) if __name__ == " __main__ " : main ()
4 days ago · List Comprehensions are a concise way to create lists in Python. They provide a syntactically compact and readable way to generate lists from existing iterables, incorporating loops and conditional logic within a single line of code. List comprehensions are particularly useful for creating new lists by applying an expression to each item in a ...
1 day ago · Explaination: concatenate two list based on their index Concatenating Lists Index Wise in Python. To concatenate two lists index-wise, you need to iterate through both lists simultaneously and combine their corresponding elements. This can be achieved using a loop or comprehensions, and the zip function is particularly handy for this purpose.
18 hours ago · List Comprehensions. List comprehensions provide a concise way to create lists in Python. They consist of an expression followed by a for clause and zero or more if clauses. The expression is evaluated for each item in the iterable specified in the for clause, and the resulting values are collected into a new list.
5 days ago · When using list comprehensions, lists can be built by leveraging any iterable, including strings and tuples.Syntactically, list comprehensions consist of an iterable containing an expression followed by a f...
1 day ago · The challenge is the temporary variable fields. Without it, the comprehension must call split (up to) three times per line: nsms = [line.split (';') for line in lines if len (line.split (';')) > 4 and line.split (';') [4] == 'NSM'] I'm not worried about the inefficiency of the redundant calls but about their impact on the expressiveness of the ...
