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  2. 2 days ago · To find the valency factor, we must first compute the number of equivalents of oxygen formed. For this, we need to first determine the equivalent weight of oxygen using the formula: $eq.wt = \dfrac{M}{v}$ Where $eq.wt$ is the equivalent weight, $M$ is the atomic weight and $v$ is the valency.

  3. 3 days ago · Identify the valence electrons. - The valence electrons are the electrons in the outermost shell. For Zinc, the outermost shell is the 4th shell, which contains the 4s electrons. - Zinc has 2 electrons in the 4s orbital. Step 4/5. Determine the common oxidation state of Zinc. - Zinc commonly loses the two 4s electrons to achieve a stable ...

  4. 4 days ago · About this video🔯🎯 Valency (संयोजकता) कैसे निकालें!How To Find Valency. for Class 9 &10 .CBSE/Bihar board exam 2025.

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  6. en.wikipedia.org › wiki › IodineIodine - Wikipedia

    4 days ago · Iodine has an electron configuration of [Kr]4d 10 5s 2 5p 5, with the seven electrons in the fifth and outermost shell being its valence electrons.

  7. en.wikipedia.org › wiki › PlatinumPlatinum - Wikipedia

    3 days ago · The most common oxidation states of platinum are +2 and +4. The +1 and +3 oxidation states are less common, and are often stabilized by metal bonding in bimetallic (or polymetallic) species. Tetracoordinate platinum (II) compounds tend to adopt 16-electron square planar geometries.

  8. en.wikipedia.org › wiki › NihoniumNihonium - Wikipedia

    4 days ago · For theoretical purposes, the valence electron configuration may be represented to reflect the 7p subshell split as 7s 2 7p 1/2 1. The first ionisation energy of nihonium is expected to be 7.306 eV , the highest among the metals of group 13. [1]

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