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The distance travelled by the ball in t = 0.2s after it attains terminal velocity is View Solution Derive expression terminal velocity when a ball of radius r is dropped thrugh a liquid of viscousity eta and density rho.
And terminal velocity is computed in meter per second i.e \(ms^{-1}\) Solved Examples for Terminal Velocity Formula. Q.1: A man is at the height of 2000 m from the ground. What would be his terminal velocity using Terminal Velocity Formula? Solution: Given, Height h = 2000 m, The terminal velocity formula is: \(V_{Terminal} = \sqrt{2 g h}\)
Solution. When a body falls in a viscous medium, it carries with its layers of fluid which are in body's contact where as the layers of fluid in contact with the stationary surface remain almost at rest. The layers of fluid destroys the relative motion and motion of the body is thus opposed. The viscous drag increases with velocity of the body ...
Molecular formula −C4H 8O2. View Solution. Q 3. A solid sphere falls with a terminal velocity of 20 m s −1 in air. If it is allowed to fall in vacuum, (a) terminal velocity will be 20 m s −1. (b) terminal velocity will be less than 20 m s −1. (c) terminal velocity will be more than 20 m s −1. (d) there will be no terminal velocity.
Click here:point_up_2:to get an answer to your question :writing_hand:state stokes law and derive it by dimensionalanalysisobtain an expression for the terminal velocity of
Escape Velocity Formula. Escape velocity refers to the minimum velocity which is needed to leave a planet or moon. For instance, for any rocket or some other object to leave a planet, it has to overcome the pull of gravity. The formula for escape velocity comprises of a constant, G, which we refer to as the universal gravitational constant.
Solution. Verified by Toppr. The terminal velocity of an object is the maximum constant velocity acquired by the object while falling freely in a viscous medium. Terminal velocity (v) of an object of radius (r) density ( ρ) moving through a viscous medius of viscosity η and density ρ 0 is given by. v = 2 9 r 2 η ( ρ − ρ 0) g.
W 1 = P 1 A 1 (v 1 ∆t) = P 1 ∆V. Moreover, if we consider the equation of continuity, the same volume of fluid will pass through BC and DE. Therefore, work done by the fluid on the right-hand side of the pipe or DE region is. W 2 = P 2 A 2 (v 2 ∆t) = P 2 ∆V. Thus, we can consider the work done on the fluid as – P 2 ∆V.
The viscous force F acting on a rain drop of radius ' a ' falling through air of coefficient of viscosity ′ η ′ with terminal velocity V is given by F α n x a y V z. The values of x , y and z are :
(Since drag force is directly proportional to velocity) A moment comes when the net upward force will be equal to net downward force as shown in the image(iii). Then the body moves with a constant speed as net acceleration on the body is zero. The speed thus acquired by the body is called terminal velocity.
