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Sep 22, 2010 · super is a keyword. It is used inside a sub-class method definition to call a method defined in the superclass. Private methods of the superclass cannot be called. Only public and protected methods can be called by the super keyword. It is also used by class constructors to invoke constructors of its parent class.
Feb 25, 2009 · Whilst when calling super.super.method(), you want to break your own obedience agreement. You just cannot cherry pick from the super class. However, there may happen situations when you feel the need to call super.super.method() - usually a bad design sign, in your code or in the code you inherit !
Apr 13, 2010 · In this cases you need to explicitly call super() from the constructor of your subclass, passing in whatever parameters you need to satisfy the base class's constructor. Also, the call to super() must be the first line of your inherited class's constructor. That last sentence is pretty important.
Nov 4, 2010 · Calling exactly super() is always redundant. It's explicitly doing what would be implicitly done otherwise. That's because if you omit a call to the super constructor, the no-argument super constructor will be invoked automatically anyway.
Jun 28, 2015 · This this refers to the reference to the current instance, also when called like this(arg) it calls the corresponding constructor in the current class. Similarly, when super() is called it calls the corresponding constructor in the super class. They can be called only from a constructor. answered May 22, 2010 at 2:06.
Jan 15, 2011 · If you want to access the methods in A, extend from A instead of B. When B extends A, it assumes that the underlying A -object won't be manipulated in other ways than how it does it itself. Therefore, by directly accessing the methods of A, you could be breaking how B functions. Imagine, for instance, you have a class that implements a list ...
Oct 26, 2010 · 9. this refers to a reference of the current class. super refers to the parent of the current class (which called the super keyword). By doing this, it allows you to access methods/attributes of the current class (including its own private methods/attributes).
Jul 11, 2013 · super () calls the default constructor of the super class. If you don't define a constructor your class always has a invisible default constructor, which doesn't require any parameters. You are calling the constructor of the Object class in this case. No, it's wrong. I thought the same.
Aug 13, 2012 · To call a method in a super class, you use super.foo(), not super().foo(). super() calls the constructor of the parent class. There is no way to call super.super.foo(). You can add a call to super.foo() in class B, so that calling super.foo() in C, will call super.foo() in B which in turn will call foo() in A. answered Aug 13, 2012 at 14:07.
Nov 23, 2016 · Super-super-class's fields (etc.) However, you didn't need to override getName() in the subclass in the first place. If you didn't define it, then it would inherit the superclass's implementation, which corresponds exactly to the behavior you wanted.
