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May 8, 2009 · There seems to be years of confusion about what this question asks. I needed to know what elements in the array were duplicated: "I just need to find what the duplicated values are". The correct answer should NOT remove duplicates from the array. That's the inverse of what I wanted: a list of the duplicates, not a list of unique elements.
Sep 2, 2015 · In this example the array is iterated, element is the same as array[i] i being the position of the array that the loop is currently on, then the function checks the position in the read array which is initialized as empty, if the element is not in the read array it'll return -1 and it'll be pushed to the read array, else it'll return its position and won't be pushed, once all the element of array has been iterated the read array will be printed to console
Feb 4, 2013 · std::sort(userNumbers, end); bool containsDuplicates = (std::unique(userNumbers, end) != end); This is the best answer. Well, the best answer would substitute unique with adjacent_find, as it doesn't check the whole container and shuffle away the duplicates, but instead just returns when it finds the first one.
I'm working on a code that prints out duplicated integers from an array with the number of their occurrence. I'm not allowed to use LINQ, just a simple code. I think I'm so close but confused about...
2. That's the simplest way I can think for finding duplicates in a list: my_list = [3, 5, 2, 1, 4, 4, 1] my_list.sort() for i in range(0,len(my_list)-1): if my_list[i] == my_list[i+1]: print str(my_list[i]) + ' is a duplicate'. answered Dec 13, 2013 at 15:37.
Jun 9, 2015 · To find all duplicates in a JavaScript array of objects based on a specific property (in this case, "name"), you can use a combination of reduce() and filter() functions. Here's a way to do it: Here's a way to do it:
Jul 18, 2012 · How can I (efficiently, Pythonically) find which elements of a are duplicates (i.e., non-unique values)? In this case the result would be array([1, 3, 3]) or possibly array([1, 3]) if efficient. I've come up with a few methods that appear to work:
Dec 17, 2009 · In Python 2.7, you can accomplish this with one line: tmp = list(set(list_a)) Comparing the lengths of tmp and list_a at this point should clarify if there were indeed duplicate items in list_a. This may help simplify things if you want to go into the loop for additional processing. edited Oct 14, 2016 at 14:11.
All it takes is just a little modification to the limits of the for loops and how you check for duplicates. The solution: Just introduce another array which is going to store the elements which are repeated in the array. Start filling this array from the 0th index as and when you find a NEWLY REPEATED element.
Dec 28, 2014 · I am trying to list out duplicate elements in an integer list using Streams of JDK 8. For example: // Duplicates are {1, 4} List<Integer> numbers = Arrays.asList(new Integer[]{1,2,1,3,4,4}); To remove duplicates we can use the distinct() method.
