Search results
The surface area of a sphere is given by the formula. Area. =. 4. π. r. 2. Where r is the radius of the sphere. In the figure above, drag the orange dot to change the radius of the sphere and note how the formula is used to calculate the surface area.
Mar 18, 2024 · Surface area of a sphere: A = 4πr², where r stands for the radius of the sphere. Surface area of a cube: A = 6a², where a is the side length. Surface area of a cylinder: A = 2πr² + 2πrh, where r is the radius and h is the height of the cylinder. Surface area of a cone: A = πr² + πr√(r² + h²), where r is the radius and h is the ...
Oct 4, 2023 · π = pi = 3.1415926535898. √ = square root. This online calculator will calculate the 3 unknown values of a sphere given any 1 known variable including radius r, surface area A, volume V and circumference C. It will also give the answers for volume, surface area and circumference in terms of PI π. A sphere is a set of points in three ...
The surface area of a capsule can be determined by combining the surface area equations for a sphere and the lateral surface area of a cylinder. Note that the surface area of the bases of the cylinder is not included since it does not comprise part of the surface area of a capsule. The total surface area is calculated as follows: SA = 4πr 2 ...
Surface area of sphere: computation and sense of formula. Why Is the formula for surface area of sphere equal to 4pir^2? And applying its formula to find the surface area.
- 5 min
- Devashish Phadnis
In the above example, the radius of the sphere is 8 cm. If the diameter is given, divide the diameter by 2 to get the radius. Step 2: Now, surface area of sphere = 4 π r 2, so after substituting the value of r = 8, we get, surface area of sphere = 4 π r 2 = 4 × 3.14 × 8 2 = 4 × 3.14 × 64 = 803.84. Step 3:
surface area of a sphere gives us just such an answer. We’ll think of our sphere as a surface of revolution formed by revolving a half circle of radius a about the x-axis. We’ll be integrating with respect to x, and we’ll let the bounds on our integral be x 1 and x 2 with −a ≤ x 1 ≤ x 2 ≤ a as sketched in Figure 1. x1 x2
