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  1. 4 days ago · Kepler's Law states that the angular momentum of a planet remains constant as it moves in an orbit around the Sun. As the areal velocity is directly dependent on the angular momentum and inversely proportional to the mass, none of these quantities are variable. Hence, the areal velocity also remains constant during planetary motion.

  2. 5 days ago · It can be found by using a formula which involves the Azimuthal quantum number. For a p shell electron, the value of Azimuthal quantum number will be one. Thus, by substituting it in the formula we get the angular momentum. Complete step by step answer: - As we know, orbital angular momentum is the analogue of angular momentum in classical ...

  3. 5 days ago · The angular momentum of electrons orbiting around according to Bohr's atomic model of the nucleus is quantized. He went on to say that electrons only move in orbits where their angular momentum is an integral multiple of\[\dfrac{h}{2}\]. Louis de Broglie later explained this postulate regarding the quantization of an electron's angular momentum.

  4. 4 days ago · So, the dimension of Planck’s constant is the same as the dimension of angular momentum. The correct answer is (A) Note: The quantity h is called the Planck’s constant.

  5. 5 days ago · Hint :In order to solve this question, we are going to first consider the masses and the radii of the discs given after which the angular speed is taken and then, the velocity of the centre of lower disc is calculated , then, angular velocity of centre of mass and angular momentum are calculated. Complete Step By Step Answer:

  6. 5 days ago · This relation is derived from Bohr’s postulates which states that angular momentum of an electron in a given stationary state can be expressed as ${m_e}vr = \dfrac{{nh}}{{2\pi }}$ , where ${m_e}$ is mass of an electron, v is velocity of an electron, r is the radius of Bohr orbital and n is the ${n^{th}}$ Bohr orbit.

  7. 5 days ago · Angular momentum changes from A to 4A. So change in angular momentum = 4A – A = 3A. Now it is given that the wheel takes 4 sec to change its angular momentum from A to 4A. So the time (t) = 4s. Now as we know that the torque acting on the circular wheel is the ratio of change in angular momentum to the time taken.

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