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2 days ago · Practice Questions on Quadratic Equations : Unsolved. 1.Solve: 9+7x=7x2. 2.If one root is twice of the other , find the quadratic equation . 3.Difference of roots is 2 and their sum is 7 , find the quadratic equation . 4.One root of mx2-10x+3=0 is two third of the other root .
4 days ago · The quadratic equation is given as follows, (4 - k)x2 + (2k + 4)x + (8k + 1) = 0. Concept: For any given quadratic equation to be a perfect square, its root needs to be equal. For equal roots of a quadratic equation of the form ax2 + bx + c = 0. b2 - 4ac = 0 or. b2 = 4ac.
3 days ago · Every quadratic equation is in the form, ${{x}^{2}}-Sx+P=0$(where ‘S’ is the sum of the roots and ‘P’ is the product the roots). We are given that one of the roots of the given equation \[{{x}^{2}}+\text{ }px\text{ }+\text{ }\left( 1\text{ }\text{- }p \right)\text{ }=\text{ }0\]is (1-p).
- 1 min
1 day ago · To solve higher degree equations, we can use substitution to convert the given equation into a quadratic equation, then solve the quadratic equation to determine the solutions to the original equation. For example, suppose we have the equation: \(ax^4+bx^2+c=0\)
- Srishta Chopra
- 2017
5 days ago · M6 - Quadratic Equations 2 M6.1 Polynomials and Introduction to Quadratic Equations CONCEPTS 1. Revision of Polynomials Division, Factor and Remainder Theorem studied upto Grade X. 2. Factorization to find the roots of a quadratic equation 3. Relation between sum and product of roots and the coefficients of a quadratic equation 4.
3 days ago · Newton's method is a powerful technique—in general the convergence is quadratic: as the method converges on the root, the difference between the root and the approximation is squared (the number of accurate digits roughly doubles) at each step. However, there are some difficulties with the method.
5 days ago · The given quadratic equation has roots whose sum is−b and product is c, where \(b=−7a\) and \(c=12a^2.\) Now, \(b^2+c=(−7a)^2+12a^2=61a^2.\) Comparing this with the given options: Option 1: \(61a^2=3721⇒a^2=61\), clearly a is not an integer. Option 2: \(61a^2=549⇒a^2=9\), which gives \(a=−3\) or \(a=3.\)
