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Contains Duplicate - Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
Contains Duplicate II - Given an integer array nums and an integer k, return true if there are two distinct indices i and j in the array such that nums[i] == nums[j] and abs(i - j) <= k.
Contains Duplicate LeetCode Solution says that- Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct. Example 1: Input: nums = [1,2,3,1] Output: true. Example 2: Input: nums = [1,2,3,4] Output: false. Example 3: Input: nums = [1,1,1,3,3,4,3,2,4,2] Output: true.
Contains Duplicate II Leetcode Solution - Check if there exists any duplicate element which are at a distance of at least k to each other.
C++ Java Python. 1 2 3 4 5 6 7 8 9 10 11 12. class Solution { public: bool containsDuplicate(vector<int>& nums) { unordered_set<int> seen; for (const int num : nums) if (!seen.insert(num).second) return true; return false; } }; 1 2 3 4 5 6 7 8 9 10 11.
Contains Duplicate III - You are given an integer array nums and two integers indexDiff and valueDiff. Find a pair of indices (i, j) such that: * i != j, * abs (i - j) <= indexDiff. * abs (nums [i] - nums [j]) <= valueDiff, and Return true if such pair exists or false otherwise.
Mar 28, 2024 · The "Contains Duplicate" problem is straightforward: you are given an integer array nums, and your task is to determine if any value appears at least twice in the array. If so, return true; otherwise, return false.
Feb 23, 2024 · To solve this problem, the approach is straightforward and involves the following steps: Initialize an empty set to track observed elements. Iterate through each element in the input list. For each...
217 Contains Duplicate - Easy Problem: Given an integer array nums , return true if any value appears at least twice in the array, and return false if every element is distinct.
Input: nums = [1,1,1,3,3,4,3,2,4,2] Output: true. Solution: The problem is straight forward. We need to check if there exists any duplicate element in the array. The brute force approach to solve this problem is to use two nested loops and check for the duplicate elements.
