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Mar 29, 2023 · Method 1: Using the Brute Force approach. Python3. def Repeat(x): _size = len(x) repeated = [] for i in range(_size): k = i + 1. for j in range(k, _size): if x[i] == x[j] and x[i] not in repeated: repeated.append(x[i]) return repeated. list1 = [10, 20, 30, 20, 20, 30, 40, . 50, -20, 60, 60, -20, -20] print (Repeat(list1))
Dec 14, 2023 · Given an array arr of N elements, the task is to find the length of the smallest subarray of the given array that contains at least one duplicate element. A subarray is formed from consecutive elements of an array.
Python program to print the duplicate elements of an array. In this program, we need to print the duplicate elements present in the array. This can be done through two loops. The first loop will select an element and the second loop will iteration through the array by comparing the selected element with other elements.
We often need to find duplicates in a list in Python. Either we need to remove them or we need to perform some operation on them or we need to find the frequency of each duplicate element. In this article, we will learn how to find duplicates in a list in Python.
def dup(x): duplicate = [] unique = [] for i in x: if i in unique: duplicate.append(i) else: unique.append(i) print("Duplicate values: ",duplicate) print("Unique Values: ",unique) list1 = [1, 2, 1, 3, 2, 5] dup(list1)
Jul 18, 2012 · This method finds both the indices of duplicates and values for distinct sets of duplicates. import numpy as np A = np.array([1,2,3,4,4,4,5,6,6,7,8]) # Record the indices where each unique element occurs. list_of_dup_inds = [np.where(a == A)[0] for a in np.unique(A)] # Filter out non-duplicates. list_of_dup_inds = filter(lambda inds: len(inds ...
Dec 17, 2009 · I have a list with duplicate elements: list_a=[1,2,3,5,6,7,5,2] tmp=[] for i in list_a: if tmp.__contains__(i): print i. else: tmp.append(i) I have used the above code to find the duplicate elements in the list_a.
