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Rotting Oranges - You are given an m x n grid where each cell can have one of three values: * 0 representing an empty cell, * 1 representing a fresh orange, or * 2 representing a rotten orange. Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
Apr 25, 2024 · Given a matrix of dimension M * N, where each cell in the matrix can have values 0, 1 or 2 which has the following meaning: 0: Empty cell. 1: Cells have fresh oranges. 2: Cells have rotten oranges. The task is to the minimum time required so that all the oranges become rotten.
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Aug 20, 2018 · 994. Rotting Oranges Description. You are given an m x n grid where each cell can have one of three values: 0 representing an empty cell, 1 representing a fresh orange, or; 2 representing a rotten orange. Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
Leetcode Link. You are given an m x n grid where each cell can have one of three values: 0 representing an empty cell, 1 representing a fresh orange, or. 2 representing a rotten orange. Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
class Solution {public: int orangesRotting (vector < vector < int >>& grid) {constexpr int dirs [4][2] = {{0, 1}, {1, 0}, {0,-1}, {-1, 0}}; const int m = grid. size (); const int n = grid [0]. size (); auto isNeighborRotten = [&](int i, int j, const vector < vector < int >>& grid) {for (const auto & [dx, dy]: dirs) {const int r = i + dx; const ...
0994 - Rotting Oranges (Medium) Problem Link. https://leetcode.com/problems/rotting-oranges/ Problem Statement. You are given an m x n grid where each cell can have one of three values: 0 representing an empty cell, 1 representing a fresh orange, or. 2 representing a rotten orange.
