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Find the Duplicate Number - Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive. There is only one repeated number in nums, return this repeated number.
Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears once or twice, return an array of all the integers that appears twice.
The problem, Find All Duplicates in an Array LeetCode Solution states that you are given an array of size n containing elements in the range [1,n]. Each integer can appear either once or twice and you need to find all the elements that appear twice in the array.
class Solution { public: vector<int> findDuplicates(vector<int>& nums) { vector<int> ans; for (const int num : nums) { nums[abs(num) - 1] *= -1; if (nums[abs(num) - 1] > 0) ans.push_back(abs(num)); } return ans; } }; LeetCode Solutions in C++20, Java, Python, MySQL, and TypeScript.
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.
LeetCode 442. Find All Duplicates in an Array (Solution Explained) The Best Place To Learn Anything Coding Related - https://bit.ly/3MFZLIZJoin my free exclusive community built to...
