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Given an integer array nums and an integer k, return the number of non-empty subarrays that have a sum divisible by k. A subarray is a contiguous part of an array. Example 1: Input: nums = [4,5,0,-2,-3,1], k = 5. Output: 7.
You are given an array A of N positive and/or negative integers and a value K. The task is to find the count of all sub-arrays whose sum is divisible by K. Example 1: Input: N = 6, K = 5 arr[] = {4, 5, 0, -2, -3, 1} Output: 7 Explanation: T
Feb 2, 2023 · The problem is to find the longest subarray’s length with the sum of the elements divisible by the given value k. Examples: Input: arr [] = {2, 7, 6, 1, 4, 5}, k = 3. Output: 4. Explanation: The subarray is {7, 6, 1, 4} with sum 18, which is divisible by 3.
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The key idea relies on the observation that if the cumulative sum from array elements nums[0] through nums[i] is sum_i, and sum_i % k equals sum_j % k for any j < i, then the subarray nums[j+1] ... nums[i] is divisible by k. This is because the cumulative sum of that subarray yields a remainder of 0 when divided by k.
class Solution: def (, nums: List [ ], k:) ->: ans = 0 prefix = 0 count = [ 0] * k count [ 0] = 1 for num nums: prefix = ( prefix + num % k + k) % k ans += count [ prefix] count [ prefix] += 1 return ans. LeetCode Solutions in C++20, Java, Python, MySQL, and TypeScript.
Aug 3, 2012 · Given an array, find how many such subsequences (does not require to be contiguous) exist where sum of elements in that subarray is divisible by K. I know an approach with complexity 2^n as given below. it is like finding all nCi where i= [0,n] and validating if sum is divisible by K.
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