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Find the zeroes, graphs and properties of polynomials using NCERT solutions for Class 10 Maths Chapter 2. Download PDFs of solutions, notes and important questions for board exams.
- Chapter 2: Solutions
The NCERT Solutions for Class 12 Chemistry can be utilised...
- Chapter 2: Solutions
Arjun seeks spiritual guidance from Shree Krishna and learns the yog of analytical knowledge. He is taught the immortal-nature of the soul, the science of work, and the transcendental state of divine consciousness.
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- RT Solutions For Class 9 Maths Chapter 2 Polynomials Ex 2.2
- RT So1utions For C1ass 9 Maths Chapter 2 Polynomials Ex 2.3
- RT So1utions For Class 9 Maths Chapter 2 Polynomials Ex 2.4
- RT Solutions For Class 9 Maths Chapter 2 Polynomials Ex 2.5
Question 1. Find the value of the polynomial 5x – 4x2 + 3 at (i) x = 0 (ii) x = – 1 (iii) x = 2 Solution: 1et p(x) = 5x – 4x2 + 3 (i) p(0) = 5(0) – 4(0)2 + 3 = 0 – 0 + 3 = 3 Thus, the value of 5x – 4x2 + 3 at x = 0 is 3. (ii) p(-1) = 5(-1) – 4(-1)2 + 3 = – 5x – 4x2 + 3 = -9 + 3 = -6 Thus, the value of 5x – 4x2 + 3 at x = -1 is -6. (iii) p(2) = 5(2)...
Question 1. Find the remainder when x3 + 3x2 + 3x + 1 is divided by (i) x + 1 (ii) x – (iii) x (iv) x + π (v) 5 + 2x Solution: Let p(x) = x3 + 3x2 + 3x +1 (i) The zero of x + 1 is -1. ∴ p(-1) = (-1)3 + 3(-1)2 + 3(-1) +1 = -1 + 3- 3 + 1 = 0 Thus, the required remainder = 0 (ii) The zero of is Thus, the required remainder = (iii) The zero of x is 0. ...
Question 1. Determine which of the following polynomials has (x +1) a factor. (i) x3+x2+x +1 (ii) x4 + x3 + x2 + x + 1 (iii) x4 + 3x3 + 3x2 + x + 1 (iv) x3 – x2 – (2 +√2 )x + √2 Solution: The zero of x + 1 is -1. (i) Let p (x) = x3 + x2 + x + 1 ∴ p (-1) = (-1)3 + (-1)2 + (-1) + 1 . = -1 + 1 – 1 + 1 ⇒ p (- 1) = 0 So, (x+ 1) is a factor of x3 + x2+ x...
Question 1. Use suitable identities to find the following products (i) (x + 4)(x + 10) (ii) (x+8) (x -10) (iii) (3x + 4) (3x – 5) (iv) (y2+ ) (y2– ) (v) (3 – 2x) (3 + 2x) Solution: (i) We have, (x+ 4) (x + 10) Using identity, (x+ a) (x+ b) = x2 + (a + b) x+ ab. We have, (x + 4) (x + 10) = x2+(4 + 10) x + (4 x 10) = x2+ 14x+40 (ii) We have, (x+ 8) (...
Sep 27, 2019 · Free download NCERT Solutions for Class 10 Science Chapter 2 Acids And Bases PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20. NCERT Solutions for Class 10 Science Chapter 2 Intext Questions
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Download free PDF of NCERT Solutions for Class 12 Chemistry Chapter 2 Solutions, covering topics such as concentration of solutions, colligative properties, and chemical equilibrium. Find important questions, answers, and examples with solutions according to the latest CBSE Syllabus for 2023-24.
Mar 31, 2024 · NCERT class 12th Chemistry chapter 2 notes Solutions by subject matter experts. Download free PDF and score more marks in exam.
