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  1. Jun 20, 2024 · HackerRank Solutions. This repository is mostly Java & PHP solutions of HackerRank Algorithms & Data Structures' Questions. However, there are some C# & Python solutions. It is one of the biggest public repository for Algorithms & Data Structures.

  2. Jun 25, 2024 · Approaches to Solve Trapping Rainwater Problem. Approach 1 – Brute Force Approach – O (N2) Time and O (1) Space. Approach 2 – Precalculation Approach – O (N) Time and O (N) Space. Approach 3 – Efficient Solution using Two Pointer Approach – O (N) Time and O (1) Space. Other Possible Approaches. Approach – Using Stack – O (N) Time and O (N) Space.

    • 14 min
  3. Jul 2, 2024 · Question 1: Find the lateral surface area and total surface area of a cuboid of length 80 cm, breadth 40 cm, and height 20 cm. Solution: Given, dimensions of cuboid are: Length(l) = 80 cm Breadth(b) = 40 cm Height(h) = 20 cm Formula for total surface area of cuboid: TSA(Cuboid) = 2[lb + bh + hl] Now, substituting the given values of in the formula,

  4. Jun 24, 2024 · Follow the below steps to solve the problem: Initialize a Max-Heap using a priority queue, say Q to keep track of the maximum element present in the array. Traverse the array arr [] and insert all the elements in heap Q. Initialize a variable, say maxProfit as 0 to store the result maximum profit obtained.

  5. Jul 10, 2024 · Determine an unknown dimension of a right cone, cylinder, prism, pyramid, or sphere, given the object’s surface area or volume and the remaining dimensions. Solve problems that involve surface area or volume, given a diagram of the composite 3-D object.

    • Monday, 1 July 2024, 9:27 PM
  6. Jul 4, 2024 · The Bharatiya Antariksh Hackathon 2024 is a premier event aimed at unearthing groundbreaking ideas and solutions in Space Tech. As India continues to make significant strides in space research and exploration, this hackathon serves as a catalyst for the next generation of innovators to contribute to the nation's space missions.

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  8. 3 days ago · To prove that the surface area of a sphere of radius r r is 4 \pi r^2 4πr2, one straightforward method we can use is calculus. We first have to realize that for a curve parameterized by x (t) x(t) and y (t y(t ), the arc length is. S = \int_a^b \sqrt { \left (\frac {dy} {dt}\right)^2 + \left ( \frac {dx} {dt}\right)^2 } \, dt.

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