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  1. Sep 24, 2024 · Given a Binary Search Tree and a SUM. The task is to check if there exists any triplet(group of 3 elements) in the given BST with the given SUM. Examples: Input : SUM = 21 Output : YES There exists a triplet (7, 3, 11) in the above given BST with sum 21. Input : SUM = 101 Output : NO It is known that elements in the inorder traversal of BST are sor

  2. class Solution: def threeSum(self, nums: List[int]) -> List[List[int]]: nums.sort() ans = [] n = len(nums) i = 0 while i < n: if nums[i] > 0: break # Since arr[i] <= arr[l] <= arr[r], if arr[i] > 0 then sum=arr[i]+arr[l]+arr[r] > 0 l = i + 1 r = n - 1 while l < r: sum3 = nums[i] + nums[l] + nums[r] if sum3 == 0: ans.append([nums[i], nums[l ...

  3. 3Sum Leetcode Solution - Given an array of n integers, are there elements a, b, c in array such that a + b + c = 0? Find all unique triplet..

  4. leetcode.com › problems › 3sum3Sum - LeetCode

    3Sum - LeetCode. Can you solve this real interview question? 3Sum - Given an integer array nums, return all the triplets [nums [i], nums [j], nums [k]] such that i != j, i != k, and j != k, and nums [i] + nums [j] + nums [k] == 0. Notice that the solution set must not contain duplicate triplets.

  5. Sep 15, 2024 · The 3Sum problem is a well-known problem where given an array of numbers and a target value, and our goal is to find three distinct numbers in the array that add up to the target value. This problem can be approached differently depending on whether the array is sorted or not.

  6. Dec 23, 2022 · In this problem, you must find all unique triplets in an array that sum up to a specific target value. Follow our clear and concise explanation to understand the approach and code for this...

  7. class Solution: def threeSum (self, nums: list [int])-> list [list [int]]: if len (nums) < 3: return [] ans = [] nums. sort for i in range (len (nums)-2): if i > 0 and nums [i] == nums [i-1]: continue # Choose nums[i] as the first number in the triplet, then search the # remaining numbers in [i + 1, n - 1]. l = i + 1 r = len (nums)-1 while l ...

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