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Given an integer array nums and an integer k, return the number of non-empty subarrays that have a sum divisible by k. A subarray is a contiguous part of an array. Example 1: Input: nums = [4,5,0,-2,-3,1], k = 5. Output: 7.
The key idea relies on the observation that if the cumulative sum from array elements nums[0] through nums[i] is sum_i, and sum_i % k equals sum_j % k for any j < i, then the subarray nums[j+1] ... nums[i] is divisible by k.
Sub-Array sum divisible by K. Difficulty: Medium Accuracy: 47.78% Submissions: 11K+ Points: 4. You are given an array A of N positive and/or negative integers and a value K. The task is to find the count of all sub-arrays whose sum is divisible by K. Example 1: Input: N = 6, K = 5. arr[] = {4, 5, 0, -2, -3, 1} Output: 7.
class Solution: def (, nums: List [ ], k:) ->: ans = 0 prefix = 0 count = [ 0] * k count [ 0] = 1 for num nums: prefix = ( prefix + num % k + k) % k ans += count [ prefix] count [ prefix] += 1 return ans. LeetCode Solutions in C++20, Java, Python, MySQL, and TypeScript.
Feb 2, 2023 · The problem is to find the longest subarray’s length with the sum of the elements divisible by the given value k. Examples: Input: arr [] = {2, 7, 6, 1, 4, 5}, k = 3. Output: 4. Explanation: The subarray is {7, 6, 1, 4} with sum 18, which is divisible by 3.
Jul 31, 2018 · Subarray Sums Divisible by K. Description. Given an integer array nums and an integer k, return the number of non-empty subarrays that have a sum divisible by k. A subarray is a contiguous part of an array. Example 1: Input: nums = [4,5,0,-2,-3,1], k = 5. Output: 7. Explanation: There are 7 subarrays with a sum divisible by k = 5:
Aug 3, 2012 · Given an array, find how many such subsequences (does not require to be contiguous) exist where sum of elements in that subarray is divisible by K. I know an approach with complexity 2^n as given below. it is like finding all nCi where i= [0,n] and validating if sum is divisible by K.
You only need to complete the function longSubarrWthSumDivByK () that takes an array arr, sizeOfArray n and a positive integer K, and returns the length of the longest subarray which has sum divisible by K. Expected Time Complexity: O (N). Expected Auxiliary Space: O (N). Constraints: 1 <= N <= 105. 1 <= K <= 109. -109 <= A [i] <= 109. Company Tags
Jan 28, 2024 · Problem Statement. Given an array of integers nums and an integer k, return the total number of continuous subarrays whose sum is divisible by k. Example: Input: nums = [4,5,0,-2,-3,1], k = 5 Output: 7 Explanation: There are 7 subarrays with a sum divisible by 5: [5], [5, 0], [5, 0, -2, -3], [0], [0, -2, -3], [-2, -3], [4, 5, 0, -2, -3, 1].
May 17, 2013 · As you are only interested in numbers divisible by K, you can do all computations modulo K. Consider the cumulative sum array S such that S[i] = S[0] + S[1] + ... + S[i]. Then (P, Q) is a slice divisible by K iff S[P] = S[Q] (remember we do all computations modulo K).
